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leetcode-problemset/leetcode-cn/originData/palindrome-partitioning-ii.json

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"categoryTitle": "Algorithms",
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"title": "Palindrome Partitioning II",
"titleSlug": "palindrome-partitioning-ii",
"content": "<p>Given a string <code>s</code>, partition <code>s</code> such that every <span data-keyword=\"substring-nonempty\">substring</span> of the partition is a <span data-keyword=\"palindrome-string\">palindrome</span>.</p>\n\n<p>Return <em>the <strong>minimum</strong> cuts needed for a palindrome partitioning of</em> <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aab&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The palindrome partitioning [&quot;aa&quot;,&quot;b&quot;] could be produced using 1 cut.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;\n<strong>Output:</strong> 0\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ab&quot;\n<strong>Output:</strong> 1\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 2000</code></li>\n\t<li><code>s</code> consists of lowercase English letters only.</li>\n</ul>\n",
"translatedTitle": "分割回文串 II",
"translatedContent": "<p>给你一个字符串 <code>s</code>,请你将 <code>s</code> 分割成一些子串,使每个子串都是回文。</p>\n\n<p>返回符合要求的 <strong>最少分割次数</strong> 。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"aab\"\n<strong>输出:</strong>1\n<strong>解释:</strong>只需一次分割就可将 <em>s </em>分割成 [\"aa\",\"b\"] 这样两个回文子串。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"a\"\n<strong>输出:</strong>0\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"ab\"\n<strong>输出:</strong>1\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 2000</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成</li>\n</ul>\n</div>\n</div>\n",
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