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"question": {
"questionId": "336",
"questionFrontendId": "336",
"categoryTitle": "Algorithms",
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"title": "Palindrome Pairs",
"titleSlug": "palindrome-pairs",
"content": "<p>You are given a <strong>0-indexed</strong> array of <strong>unique</strong> strings <code>words</code>.</p>\n\n<p>A <strong>palindrome pair</strong> is a pair of integers <code>(i, j)</code> such that:</p>\n\n<ul>\n\t<li><code>0 &lt;= i, j &lt; words.length</code>,</li>\n\t<li><code>i != j</code>, and</li>\n\t<li><code>words[i] + words[j]</code> (the concatenation of the two strings) is a <span data-keyword=\"palindrome-string\">palindrome</span>.</li>\n</ul>\n\n<p>Return <em>an array of all the <strong>palindrome pairs</strong> of </em><code>words</code>.</p>\n\n<p>You must write an algorithm with&nbsp;<code>O(sum of words[i].length)</code>&nbsp;runtime complexity.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;abcd&quot;,&quot;dcba&quot;,&quot;lls&quot;,&quot;s&quot;,&quot;sssll&quot;]\n<strong>Output:</strong> [[0,1],[1,0],[3,2],[2,4]]\n<strong>Explanation:</strong> The palindromes are [&quot;abcddcba&quot;,&quot;dcbaabcd&quot;,&quot;slls&quot;,&quot;llssssll&quot;]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;bat&quot;,&quot;tab&quot;,&quot;cat&quot;]\n<strong>Output:</strong> [[0,1],[1,0]]\n<strong>Explanation:</strong> The palindromes are [&quot;battab&quot;,&quot;tabbat&quot;]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;a&quot;,&quot;&quot;]\n<strong>Output:</strong> [[0,1],[1,0]]\n<strong>Explanation:</strong> The palindromes are [&quot;a&quot;,&quot;a&quot;]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 5000</code></li>\n\t<li><code>0 &lt;= words[i].length &lt;= 300</code></li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "回文对",
"translatedContent": "<p>给定一个由唯一字符串构成的 <strong>0 索引&nbsp;</strong>数组 <code>words</code>&nbsp;。</p>\n\n<p><strong>回文对</strong> 是一对整数 <code>(i, j)</code> ,满足以下条件:</p>\n\n<ul>\n\t<li><code>0 &lt;= i, j &lt; words.length</code></li>\n\t<li><code>i != j</code> ,并且</li>\n\t<li><code>words[i] + words[j]</code>(两个字符串的连接)是一个回文。</li>\n</ul>\n\n<p>返回一个数组,它包含&nbsp;<code>words</code> 中所有满足 <strong>回文对</strong> 条件的字符串。</p>\n\n<p>你必须设计一个时间复杂度为 <code>O(sum of words[i].length)</code> 的算法。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"abcd\",\"dcba\",\"lls\",\"s\",\"sssll\"]\n<strong>输出:</strong>[[0,1],[1,0],[3,2],[2,4]] \n<strong>解释:</strong>可拼接成的回文串为 <code>[\"dcbaabcd\",\"abcddcba\",\"slls\",\"llssssll\"]</code>\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"bat\",\"tab\",\"cat\"]\n<strong>输出:</strong>[[0,1],[1,0]] \n<strong>解释:</strong>可拼接成的回文串为 <code>[\"battab\",\"tabbat\"]</code></pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>words = [\"a\",\"\"]\n<strong>输出:</strong>[[0,1],[1,0]]\n</pre>\n&nbsp;\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 5000</code></li>\n\t<li><code>0 &lt;= words[i].length &lt;= 300</code></li>\n\t<li><code>words[i]</code> 由小写英文字母组成</li>\n</ul>\n",
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"code": "class Solution {\npublic:\n vector<vector<int>> palindromePairs(vector<string>& words) {\n \n }\n};",
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"code": "class Solution(object):\n def palindromePairs(self, words):\n \"\"\"\n :type words: List[str]\n :rtype: List[List[int]]\n \"\"\"",
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"code": "/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** palindromePairs(char** words, int wordsSize, int* returnSize, int** returnColumnSizes) {\n \n}",
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"code": "defmodule Solution do\n @spec palindrome_pairs(words :: [String.t]) :: [[integer]]\n def palindrome_pairs(words) do\n \n end\nend",
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"hints": [
"Checking every two pairs will exceed the time limit. It will be O(n^2 * k). We need a faster way.",
"If we hash every string in the array, how can we check if two pairs form a palindrome after the concatenation?",
"We can check every string in words and consider it as words[j] (i.e., the suffix of the target palindrome). We can check if there is a hash of string that can be the prefix to make it a palindrome."
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