mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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184 lines
21 KiB
JSON
184 lines
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"title": "Minimum Sum of Four Digit Number After Splitting Digits",
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"content": "<p>You are given a <strong>positive</strong> integer <code>num</code> consisting of exactly four digits. Split <code>num</code> into two new integers <code>new1</code> and <code>new2</code> by using the <strong>digits</strong> found in <code>num</code>. <strong>Leading zeros</strong> are allowed in <code>new1</code> and <code>new2</code>, and <strong>all</strong> the digits found in <code>num</code> must be used.</p>\n\n<ul>\n\t<li>For example, given <code>num = 2932</code>, you have the following digits: two <code>2</code>'s, one <code>9</code> and one <code>3</code>. Some of the possible pairs <code>[new1, new2]</code> are <code>[22, 93]</code>, <code>[23, 92]</code>, <code>[223, 9]</code> and <code>[2, 329]</code>.</li>\n</ul>\n\n<p>Return <em>the <strong>minimum</strong> possible sum of </em><code>new1</code><em> and </em><code>new2</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 2932\n<strong>Output:</strong> 52\n<strong>Explanation:</strong> Some possible pairs [new1, new2] are [29, 23], [223, 9], etc.\nThe minimum sum can be obtained by the pair [29, 23]: 29 + 23 = 52.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 4009\n<strong>Output:</strong> 13\n<strong>Explanation:</strong> Some possible pairs [new1, new2] are [0, 49], [490, 0], etc. \nThe minimum sum can be obtained by the pair [4, 9]: 4 + 9 = 13.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1000 <= num <= 9999</code></li>\n</ul>\n",
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"translatedTitle": "拆分数位后四位数字的最小和",
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"translatedContent": "<p>给你一个四位 <strong>正</strong> 整数 <code>num</code> 。请你使用 <code>num</code> 中的 <strong>数位</strong> ,将 <code>num</code> 拆成两个新的整数 <code>new1</code> 和 <code>new2</code> 。<code>new1</code> 和 <code>new2</code> 中可以有 <strong>前导 0</strong> ,且 <code>num</code> 中 <strong>所有</strong> 数位都必须使用。</p>\n\n<ul>\n\t<li>比方说,给你 <code>num = 2932</code> ,你拥有的数位包括:两个 <code>2</code> ,一个 <code>9</code> 和一个 <code>3</code> 。一些可能的 <code>[new1, new2]</code> 数对为 <code>[22, 93]</code>,<code>[23, 92]</code>,<code>[223, 9]</code> 和 <code>[2, 329]</code> 。</li>\n</ul>\n\n<p>请你返回可以得到的 <code>new1</code> 和 <code>new2</code> 的 <strong>最小</strong> 和。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><b>输入:</b>num = 2932\n<b>输出:</b>52\n<b>解释:</b>可行的 [new1, new2] 数对为 [29, 23] ,[223, 9] 等等。\n最小和为数对 [29, 23] 的和:29 + 23 = 52 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><b>输入:</b>num = 4009\n<b>输出:</b>13\n<b>解释:</b>可行的 [new1, new2] 数对为 [0, 49] ,[490, 0] 等等。\n最小和为数对 [4, 9] 的和:4 + 9 = 13 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1000 <= num <= 9999</code></li>\n</ul>\n",
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"Notice that the most optimal way to obtain the minimum possible sum using 4 digits is by summing up two 2-digit numbers.",
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"We can use the two smallest digits out of the four as the digits found in the tens place respectively.",
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"Similarly, we use the final 2 larger digits as the digits found in the ones place."
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