leetcode-problemset/leetcode-cn/originData/minimum-replacements-to-sort-the-array.json

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            "title": "Minimum Replacements to Sort the Array",
            "titleSlug": "minimum-replacements-to-sort-the-array",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>. In one operation you can replace any element of the array with <strong>any two</strong> elements that <strong>sum</strong> to it.</p>\n\n<ul>\n\t<li>For example, consider <code>nums = [5,6,7]</code>. In one operation, we can replace <code>nums[1]</code> with <code>2</code> and <code>4</code> and convert <code>nums</code> to <code>[5,2,4,7]</code>.</li>\n</ul>\n\n<p>Return <em>the minimum number of operations to make an array that is sorted in <strong>non-decreasing</strong> order</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,9,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Here are the steps to sort the array in non-decreasing order:\n- From [3,9,3], replace the 9 with 3 and 6 so the array becomes [3,3,6,3]\n- From [3,3,6,3], replace the 6 with 3 and 3 so the array becomes [3,3,3,3,3]\nThere are 2 steps to sort the array in non-decreasing order. Therefore, we return 2.\n\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The array is already in non-decreasing order. Therefore, we return 0. \n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "将数组排序的最少替换次数",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;。每次操作中，你可以将数组中任何一个元素替换为&nbsp;<strong>任意两个</strong>&nbsp;和为该元素的数字。</p>\n\n<ul>\n\t<li>比方说，<code>nums = [5,6,7]</code>&nbsp;。一次操作中，我们可以将&nbsp;<code>nums[1]</code> 替换成&nbsp;<code>2</code> 和&nbsp;<code>4</code>&nbsp;，将&nbsp;<code>nums</code>&nbsp;转变成&nbsp;<code>[5,2,4,7]</code>&nbsp;。</li>\n</ul>\n\n<p>请你执行上述操作，将数组变成元素按 <strong>非递减</strong> 顺序排列的数组，并返回所需的最少操作次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [3,9,3]\n<b>输出：</b>2\n<b>解释：</b>以下是将数组变成非递减顺序的步骤：\n- [3,9,3] ，将9 变成 3 和 6 ，得到数组 [3,3,6,3] \n- [3,3,6,3] ，将 6 变成 3 和 3 ，得到数组 [3,3,3,3,3] \n总共需要 2 步将数组变成非递减有序，所以我们返回 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,2,3,4,5]\n<b>输出：</b>0\n<b>解释：</b>数组已经是非递减顺序，所以我们返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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