leetcode-problemset/leetcode-cn/originData/minimum-operations-to-reduce-an-integer-to-0.json

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            "title": "Minimum Operations to Reduce an Integer to 0",
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            "content": "<p>You are given a positive integer <code>n</code>, you can do the following operation <strong>any</strong> number of times:</p>\n\n<ul>\n\t<li>Add or subtract a <strong>power</strong> of <code>2</code> from <code>n</code>.</li>\n</ul>\n\n<p>Return <em>the <strong>minimum</strong> number of operations to make </em><code>n</code><em> equal to </em><code>0</code>.</p>\n\n<p>A number <code>x</code> is power of <code>2</code> if <code>x == 2<sup>i</sup></code>&nbsp;where <code>i &gt;= 0</code><em>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 39\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can do the following operations:\n- Add 2<sup>0</sup> = 1 to n, so now n = 40.\n- Subtract 2<sup>3</sup> = 8 from n, so now n = 32.\n- Subtract 2<sup>5</sup> = 32 from n, so now n = 0.\nIt can be shown that 3 is the minimum number of operations we need to make n equal to 0.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 54\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can do the following operations:\n- Add 2<sup>1</sup> = 2 to n, so now n = 56.\n- Add 2<sup>3</sup> = 8 to n, so now n = 64.\n- Subtract 2<sup>6</sup> = 64 from n, so now n = 0.\nSo the minimum number of operations is 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "将整数减少到零需要的最少操作数",
            "translatedContent": "<p>给你一个正整数 <code>n</code> ，你可以执行下述操作 <strong>任意</strong> 次：</p>\n\n<ul>\n\t<li><code>n</code> 加上或减去 <code>2</code> 的某个 <strong>幂</strong></li>\n</ul>\n\n<p>返回使 <code>n</code> 等于 <code>0</code> 需要执行的 <strong>最少</strong> 操作数。</p>\n\n<p>如果 <code>x == 2<sup>i</sup></code> 且其中 <code>i &gt;= 0</code> ，则数字 <code>x</code> 是 <code>2</code> 的幂。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 39\n<strong>输出：</strong>3\n<strong>解释：</strong>我们可以执行下述操作：\n- n 加上 2<sup>0</sup> = 1 ，得到 n = 40 。\n- n 减去 2<sup>3</sup> = 8 ，得到 n = 32 。\n- n 减去 2<sup>5</sup> = 32 ，得到 n = 0 。\n可以证明使 n 等于 0 需要执行的最少操作数是 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 54\n<strong>输出：</strong>3\n<strong>解释：</strong>我们可以执行下述操作：\n- n 加上 2<sup>1</sup> = 2 ，得到 n = 56 。\n- n 加上 2<sup>3</sup> = 8 ，得到 n = 64 。\n- n 减去 2<sup>6</sup> = 64 ，得到 n = 0 。\n使 n 等于 0 需要执行的最少操作数是 3 。 \n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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