leetcode-problemset/leetcode-cn/originData/minimum-difficulty-of-a-job-schedule.json

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            "title": "Minimum Difficulty of a Job Schedule",
            "titleSlug": "minimum-difficulty-of-a-job-schedule",
            "content": "<p>You want to schedule a list of jobs in <code>d</code> days. Jobs are dependent (i.e To work on the <code>i<sup>th</sup></code> job, you have to finish all the jobs <code>j</code> where <code>0 &lt;= j &lt; i</code>).</p>\n\n<p>You have to finish <strong>at least</strong> one task every day. The difficulty of a job schedule is the sum of difficulties of each day of the <code>d</code> days. The difficulty of a day is the maximum difficulty of a job done on that day.</p>\n\n<p>You are given an integer array <code>jobDifficulty</code> and an integer <code>d</code>. The difficulty of the <code>i<sup>th</sup></code> job is <code>jobDifficulty[i]</code>.</p>\n\n<p>Return <em>the minimum difficulty of a job schedule</em>. If you cannot find a schedule for the jobs return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/01/16/untitled.png\" style=\"width: 365px; height: 370px;\" />\n<pre>\n<strong>Input:</strong> jobDifficulty = [6,5,4,3,2,1], d = 2\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> First day you can finish the first 5 jobs, total difficulty = 6.\nSecond day you can finish the last job, total difficulty = 1.\nThe difficulty of the schedule = 6 + 1 = 7 \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> jobDifficulty = [9,9,9], d = 4\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> If you finish a job per day you will still have a free day. you cannot find a schedule for the given jobs.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> jobDifficulty = [1,1,1], d = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The schedule is one job per day. total difficulty will be 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= jobDifficulty.length &lt;= 300</code></li>\n\t<li><code>0 &lt;= jobDifficulty[i] &lt;= 1000</code></li>\n\t<li><code>1 &lt;= d &lt;= 10</code></li>\n</ul>\n",
            "translatedTitle": "工作计划的最低难度",
            "translatedContent": "<p>你需要制定一份&nbsp;<code>d</code>&nbsp;天的工作计划表。工作之间存在依赖，要想执行第&nbsp;<code>i</code>&nbsp;项工作，你必须完成全部&nbsp;<code>j</code>&nbsp;项工作（&nbsp;<code>0 &lt;= j &lt; i</code>）。</p>\n\n<p>你每天 <strong>至少</strong>&nbsp;需要完成一项任务。工作计划的总难度是这&nbsp;<code>d</code>&nbsp;天每一天的难度之和，而一天的工作难度是当天应该完成工作的最大难度。</p>\n\n<p>给你一个整数数组&nbsp;<code>jobDifficulty</code>&nbsp;和一个整数&nbsp;<code>d</code>，分别代表工作难度和需要计划的天数。第&nbsp;<code>i</code>&nbsp;项工作的难度是&nbsp;<code>jobDifficulty[i]</code>。</p>\n\n<p>返回整个工作计划的 <strong>最小难度</strong> 。如果无法制定工作计划，则返回&nbsp;<strong>-1&nbsp;</strong>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/01/26/untitled.png\" style=\"height: 304px; width: 365px;\"></p>\n\n<pre><strong>输入：</strong>jobDifficulty = [6,5,4,3,2,1], d = 2\n<strong>输出：</strong>7\n<strong>解释：</strong>第一天，您可以完成前 5 项工作，总难度 = 6.\n第二天，您可以完成最后一项工作，总难度 = 1.\n计划表的难度 = 6 + 1 = 7 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>jobDifficulty = [9,9,9], d = 4\n<strong>输出：</strong>-1\n<strong>解释：</strong>就算你每天完成一项工作，仍然有一天是空闲的，你无法制定一份能够满足既定工作时间的计划表。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>jobDifficulty = [1,1,1], d = 3\n<strong>输出：</strong>3\n<strong>解释：</strong>工作计划为每天一项工作，总难度为 3 。\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre><strong>输入：</strong>jobDifficulty = [7,1,7,1,7,1], d = 3\n<strong>输出：</strong>15\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre><strong>输入：</strong>jobDifficulty = [11,111,22,222,33,333,44,444], d = 6\n<strong>输出：</strong>843\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= jobDifficulty.length &lt;= 300</code></li>\n\t<li><code>0 &lt;=&nbsp;jobDifficulty[i] &lt;= 1000</code></li>\n\t<li><code>1 &lt;= d &lt;= 10</code></li>\n</ul>\n",
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