mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
190 lines
22 KiB
JSON
190 lines
22 KiB
JSON
{
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"questionId": "1805",
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"questionFrontendId": "1703",
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"categoryTitle": "Algorithms",
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"boundTopicId": 535084,
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"title": "Minimum Adjacent Swaps for K Consecutive Ones",
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"content": "<p>You are given an integer array, <code>nums</code>, and an integer <code>k</code>. <code>nums</code> comprises of only <code>0</code>'s and <code>1</code>'s. In one move, you can choose two <strong>adjacent</strong> indices and swap their values.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of moves required so that </em><code>nums</code><em> has </em><code>k</code><em> <strong>consecutive</strong> </em><code>1</code><em>'s</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,0,0,1,0,1], k = 2\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> In 1 move, nums could be [1,0,0,0,<u>1</u>,<u>1</u>] and have 2 consecutive 1's.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,0,0,0,0,0,1,1], k = 3\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> In 5 moves, the leftmost 1 can be shifted right until nums = [0,0,0,0,0,<u>1</u>,<u>1</u>,<u>1</u>].\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,0,1], k = 2\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> nums already has 2 consecutive 1's.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>nums[i]</code> is <code>0</code> or <code>1</code>.</li>\n\t<li><code>1 <= k <= sum(nums)</code></li>\n</ul>\n",
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"translatedTitle": "得到连续 K 个 1 的最少相邻交换次数",
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"translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code> 。 <code>nums</code> 仅包含 <code>0</code> 和 <code>1</code> 。每一次移动，你可以选择 <strong>相邻</strong> 两个数字并将它们交换。</p>\n\n<p>请你返回使 <code>nums</code> 中包含 <code>k</code> 个 <strong>连续 </strong><code>1</code> 的 <strong>最少</strong> 交换次数。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [1,0,0,1,0,1], k = 2\n<b>输出：</b>1\n<b>解释：</b>在第一次操作时，nums 可以变成 [1,0,0,0,<strong>1</strong>,<strong>1</strong>] 得到连续两个 1 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,0,0,0,0,0,1,1], k = 3\n<b>输出：</b>5\n<b>解释：</b>通过 5 次操作，最左边的 1 可以移到右边直到 nums 变为 [0,0,0,0,0,<strong>1</strong>,<strong>1</strong>,<strong>1</strong>] 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>nums = [1,1,0,1], k = 2\n<b>输出：</b>0\n<b>解释：</b>nums 已经有连续 2 个 1 了。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>nums[i]</code> 要么是 <code>0</code> ，要么是 <code>1</code> 。</li>\n\t<li><code>1 <= k <= sum(nums)</code></li>\n</ul>\n",
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"Choose k 1s and determine how many steps are required to move them into 1 group.",
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"Maintain a sliding window of k 1s, and maintain the steps required to group them.",
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"When you slide the window across, should you move the group to the right? Once you move the group to the right, it will never need to slide to the left again."
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