mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
28 KiB
JSON
186 lines
28 KiB
JSON
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"categoryTitle": "Algorithms",
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"boundTopicId": 1085,
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"title": "Maximum Width of Binary Tree",
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"titleSlug": "maximum-width-of-binary-tree",
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"content": "<p>Given the <code>root</code> of a binary tree, return <em>the <strong>maximum width</strong> of the given tree</em>.</p>\n\n<p>The <strong>maximum width</strong> of a tree is the maximum <strong>width</strong> among all levels.</p>\n\n<p>The <strong>width</strong> of one level is defined as the length between the end-nodes (the leftmost and rightmost non-null nodes), where the null nodes between the end-nodes that would be present in a complete binary tree extending down to that level are also counted into the length calculation.</p>\n\n<p>It is <strong>guaranteed</strong> that the answer will in the range of a <strong>32-bit</strong> signed integer.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/03/width1-tree.jpg\" style=\"width: 359px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> root = [1,3,2,5,3,null,9]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The maximum width exists in the third level with length 4 (5,3,null,9).\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/14/maximum-width-of-binary-tree-v3.jpg\" style=\"width: 442px; height: 422px;\" />\n<pre>\n<strong>Input:</strong> root = [1,3,2,5,null,null,9,6,null,7]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> The maximum width exists in the fourth level with length 7 (6,null,null,null,null,null,7).\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/03/width3-tree.jpg\" style=\"width: 289px; height: 299px;\" />\n<pre>\n<strong>Input:</strong> root = [1,3,2,5]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The maximum width exists in the second level with length 2 (3,2).\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 3000]</code>.</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n</ul>\n",
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"translatedTitle": "二叉树最大宽度",
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"translatedContent": "<p>给你一棵二叉树的根节点 <code>root</code> ，返回树的 <strong>最大宽度</strong> 。</p>\n\n<p>树的 <strong>最大宽度</strong> 是所有层中最大的 <strong>宽度</strong> 。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p>每一层的 <strong>宽度</strong> 被定义为该层最左和最右的非空节点（即，两个端点）之间的长度。将这个二叉树视作与满二叉树结构相同，两端点间会出现一些延伸到这一层的 <code>null</code> 节点，这些 <code>null</code> 节点也计入长度。</p>\n\n<p>题目数据保证答案将会在 <strong>32 位</strong> 带符号整数范围内。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/03/width1-tree.jpg\" style=\"width: 359px; height: 302px;\" />\n<pre>\n<strong>输入：</strong>root = [1,3,2,5,3,null,9]\n<strong>输出：</strong>4\n<strong>解释：</strong>最大宽度出现在树的第 3 层，宽度为 4 (5,3,null,9) 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/03/14/maximum-width-of-binary-tree-v3.jpg\" style=\"width: 442px; height: 422px;\" />\n<pre>\n<strong>输入：</strong>root = [1,3,2,5,null,null,9,6,null,7]\n<strong>输出：</strong>7\n<strong>解释：</strong>最大宽度出现在树的第 4 层，宽度为 7 (6,null,null,null,null,null,7) 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/03/width3-tree.jpg\" style=\"width: 289px; height: 299px;\" />\n<pre>\n<strong>输入：</strong>root = [1,3,2,5]\n<strong>输出：</strong>2\n<strong>解释：</strong>最大宽度出现在树的第 2 层，宽度为 2 (3,2) 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点的数目范围是 <code>[1, 3000]</code></li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n</ul>\n</div>\n</div>\n",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def widthOfBinaryTree(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction widthOfBinaryTree(root: TreeNode | null): number {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer\n */\n function widthOfBinaryTree($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func widthOfBinaryTree(_ root: TreeNode?) -> Int {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun widthOfBinaryTree(root: TreeNode?): Int {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef width_of_binary_tree(root)\n\nend",
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