mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
201 lines
21 KiB
JSON
201 lines
21 KiB
JSON
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"questionId": "718",
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"questionFrontendId": "718",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1826,
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"title": "Maximum Length of Repeated Subarray",
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"content": "<p>Given two integer arrays <code>nums1</code> and <code>nums2</code>, return <em>the maximum length of a subarray that appears in <strong>both</strong> arrays</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2,3,2,1], nums2 = [3,2,1,4,7]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The repeated subarray with maximum length is [3,2,1].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [0,0,0,0,0], nums2 = [0,0,0,0,0]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The repeated subarray with maximum length is [0,0,0,0,0].\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums1.length, nums2.length <= 1000</code></li>\n\t<li><code>0 <= nums1[i], nums2[i] <= 100</code></li>\n</ul>\n",
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"translatedTitle": "最长重复子数组",
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"translatedContent": "<p>给两个整数数组 <code>nums1</code> 和 <code>nums2</code> ，返回 <em>两个数组中 <strong>公共的</strong> 、长度最长的子数组的长度 </em>。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,2,3,2,1], nums2 = [3,2,1,4,7]\n<strong>输出：</strong>3\n<strong>解释：</strong>长度最长的公共子数组是 [3,2,1] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [0,0,0,0,0], nums2 = [0,0,0,0,0]\n<strong>输出：</strong>5\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums1.length, nums2.length <= 1000</code></li>\n\t<li><code>0 <= nums1[i], nums2[i] <= 100</code></li>\n</ul>\n",
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"Use dynamic programming. dp[i][j] will be the longest common prefix of A[i:] and B[j:].",
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"The answer is max(dp[i][j]) over all i, j."
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