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"data": {
"question": {
"questionId": "1484",
"questionFrontendId": "1367",
"categoryTitle": "Algorithms",
"boundTopicId": 112539,
"title": "Linked List in Binary Tree",
"titleSlug": "linked-list-in-binary-tree",
"content": "<p>Given a binary tree <code>root</code> and a&nbsp;linked list with&nbsp;<code>head</code>&nbsp;as the first node.&nbsp;</p>\n\n<p>Return True if all the elements in the linked list starting from the <code>head</code> correspond to some <em>downward path</em> connected in the binary tree&nbsp;otherwise return False.</p>\n\n<p>In this context downward path means a path that starts at some node and goes downwards.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/sample_1_1720.png\" style=\"width: 220px; height: 280px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> head = [4,2,8], root = [1,4,4,null,2,2,null,1,null,6,8,null,null,null,null,1,3]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Nodes in blue form a subpath in the binary Tree. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/12/sample_2_1720.png\" style=\"width: 220px; height: 280px;\" /></strong></p>\n\n<pre>\n<strong>Input:</strong> head = [1,4,2,6], root = [1,4,4,null,2,2,null,1,null,6,8,null,null,null,null,1,3]\n<strong>Output:</strong> true\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> head = [1,4,2,6,8], root = [1,4,4,null,2,2,null,1,null,6,8,null,null,null,null,1,3]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> There is no path in the binary tree that contains all the elements of the linked list from <code>head</code>.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree will be in the range <code>[1, 2500]</code>.</li>\n\t<li>The number of nodes in the list will be in the range <code>[1, 100]</code>.</li>\n\t<li><code>1 &lt;= Node.val&nbsp;&lt;= 100</code>&nbsp;for each node in the linked list and binary tree.</li>\n</ul>\n",
"translatedTitle": "二叉树中的链表",
"translatedContent": "<p>给你一棵以&nbsp;<code>root</code>&nbsp;为根的二叉树和一个&nbsp;<code>head</code>&nbsp;为第一个节点的链表。</p>\n\n<p>如果在二叉树中,存在一条一直向下的路径,且每个点的数值恰好一一对应以&nbsp;<code>head</code>&nbsp;为首的链表中每个节点的值,那么请你返回 <code>True</code> ,否则返回 <code>False</code> 。</p>\n\n<p>一直向下的路径的意思是:从树中某个节点开始,一直连续向下的路径。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/02/29/sample_1_1720.png\" style=\"height: 280px; width: 220px;\"></strong></p>\n\n<pre><strong>输入:</strong>head = [4,2,8], root = [1,4,4,null,2,2,null,1,null,6,8,null,null,null,null,1,3]\n<strong>输出:</strong>true\n<strong>解释:</strong>树中蓝色的节点构成了与链表对应的子路径。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/02/29/sample_2_1720.png\" style=\"height: 280px; width: 220px;\"></strong></p>\n\n<pre><strong>输入:</strong>head = [1,4,2,6], root = [1,4,4,null,2,2,null,1,null,6,8,null,null,null,null,1,3]\n<strong>输出:</strong>true\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre><strong>输入:</strong>head = [1,4,2,6,8], root = [1,4,4,null,2,2,null,1,null,6,8,null,null,null,null,1,3]\n<strong>输出:</strong>false\n<strong>解释:</strong>二叉树中不存在一一对应链表的路径。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>二叉树和链表中的每个节点的值都满足&nbsp;<code>1 &lt;= node.val&nbsp;&lt;= 100</code>&nbsp;。</li>\n\t<li>链表包含的节点数目在&nbsp;<code>1</code>&nbsp;到&nbsp;<code>100</code>&nbsp;之间。</li>\n\t<li>二叉树包含的节点数目在&nbsp;<code>1</code>&nbsp;到&nbsp;<code>2500</code>&nbsp;之间。</li>\n</ul>\n",
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"code": "# Definition for singly-linked list.\n# class ListNode\n# attr_accessor :val, :next\n# def initialize(val = 0, _next = nil)\n# @val = val\n# @next = _next\n# end\n# end\n# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {ListNode} head\n# @param {TreeNode} root\n# @return {Boolean}\ndef is_sub_path(head, root)\n\nend",
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"code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%% next = null :: 'null' | #list_node{}}).\n\n%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec is_sub_path(Head :: #list_node{} | null, Root :: #tree_node{} | null) -> boolean().\nis_sub_path(Head, Root) ->\n .",
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"code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# next: ListNode.t() | nil\n# }\n# defstruct val: 0, next: nil\n# end\n\n# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec is_sub_path(head :: ListNode.t | nil, root :: TreeNode.t | nil) :: boolean\n def is_sub_path(head, root) do\n \n end\nend",
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