leetcode-problemset/leetcode-cn/originData/largest-multiple-of-three.json

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            "categoryTitle": "Algorithms",
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            "title": "Largest Multiple of Three",
            "titleSlug": "largest-multiple-of-three",
            "content": "<p>Given an array of digits <code>digits</code>, return <em>the largest multiple of <strong>three</strong> that can be formed by concatenating some of the given digits in <strong>any order</strong></em>. If there is no answer return an empty string.</p>\n\n<p>Since the answer may not fit in an integer data type, return the answer as a string. Note that the returning answer must not contain unnecessary leading zeros.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> digits = [8,1,9]\n<strong>Output:</strong> &quot;981&quot;\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> digits = [8,6,7,1,0]\n<strong>Output:</strong> &quot;8760&quot;\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> digits = [1]\n<strong>Output:</strong> &quot;&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= digits.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= digits[i] &lt;= 9</code></li>\n</ul>\n",
            "translatedTitle": "形成三的最大倍数",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>digits</code>，你可以通过按 <strong>任意顺序</strong> 连接其中某些数字来形成 <strong>3</strong> 的倍数，请你返回所能得到的最大的 3 的倍数。</p>\n\n<p>由于答案可能不在整数数据类型范围内，请以字符串形式返回答案。如果无法得到答案，请返回一个空字符串。返回的结果不应包含不必要的前导零。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>digits = [8,1,9]\n<strong>输出：</strong>\"981\"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>digits = [8,6,7,1,0]\n<strong>输出：</strong>\"8760\"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>digits = [1]\n<strong>输出：</strong>\"\"\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>digits = [0,0,0,0,0,0]\n<strong>输出：</strong>\"0\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= digits.length &lt;= 10^4</code></li>\n\t<li><code>0 &lt;= digits[i] &lt;= 9</code></li>\n</ul>\n",
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            "hints": [
                "A number is a multiple of three if and only if its sum of digits is a multiple of three.",
                "Use dynamic programming.",
                "To find the maximum number, try to maximize the number of digits of the number.",
                "Sort the digits in descending order to find the maximum number."
            ],
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