mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
191 lines
27 KiB
JSON
191 lines
27 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "230",
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"questionFrontendId": "230",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1451,
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"title": "Kth Smallest Element in a BST",
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"titleSlug": "kth-smallest-element-in-a-bst",
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"content": "<p>Given the <code>root</code> of a binary search tree, and an integer <code>k</code>, return <em>the</em> <code>k<sup>th</sup></code> <em>smallest value (<strong>1-indexed</strong>) of all the values of the nodes in the tree</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/28/kthtree1.jpg\" style=\"width: 212px; height: 301px;\" />\n<pre>\n<strong>Input:</strong> root = [3,1,4,null,2], k = 1\n<strong>Output:</strong> 1\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/28/kthtree2.jpg\" style=\"width: 382px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> root = [5,3,6,2,4,null,null,1], k = 3\n<strong>Output:</strong> 3\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is <code>n</code>.</li>\n\t<li><code>1 <= k <= n <= 10<sup>4</sup></code></li>\n\t<li><code>0 <= Node.val <= 10<sup>4</sup></code></li>\n</ul>\n\n<p> </p>\n<p><strong>Follow up:</strong> If the BST is modified often (i.e., we can do insert and delete operations) and you need to find the kth smallest frequently, how would you optimize?</p>\n",
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"translatedTitle": "二叉搜索树中第K小的元素",
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"translatedContent": "<p>给定一个二叉搜索树的根节点 <code>root</code> ，和一个整数 <code>k</code> ，请你设计一个算法查找其中第 <code>k</code><strong> </strong>个最小元素（从 1 开始计数）。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/28/kthtree1.jpg\" style=\"width: 212px; height: 301px;\" />\n<pre>\n<strong>输入：</strong>root = [3,1,4,null,2], k = 1\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/28/kthtree2.jpg\" style=\"width: 382px; height: 302px;\" />\n<pre>\n<strong>输入：</strong>root = [5,3,6,2,4,null,null,1], k = 3\n<strong>输出：</strong>3\n</pre>\n\n<p> </p>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的节点数为 <code>n</code> 。</li>\n\t<li><code>1 <= k <= n <= 10<sup>4</sup></code></li>\n\t<li><code>0 <= Node.val <= 10<sup>4</sup></code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>如果二叉搜索树经常被修改（插入/删除操作）并且你需要频繁地查找第 <code>k</code> 小的值，你将如何优化算法？</p>\n",
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"difficulty": "Medium",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def kthSmallest(self, root, k):\n \"\"\"\n :type root: TreeNode\n :type k: int\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public int KthSmallest(TreeNode root, int k) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} k\n * @return {number}\n */\nvar kthSmallest = function(root, k) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction kthSmallest(root: TreeNode | null, k: number): number {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $k\n * @return Integer\n */\n function kthSmallest($root, $k) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func kthSmallest(_ root: TreeNode?, _ k: Int) -> Int {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun kthSmallest(root: TreeNode?, k: Int): Int {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n int kthSmallest(TreeNode? root, int k) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc kthSmallest(root *TreeNode, k int) int {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} k\n# @return {Integer}\ndef kth_smallest(root, k)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def kthSmallest(root: TreeNode, k: Int): Int = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn kth_smallest(root: Option<Rc<RefCell<TreeNode>>>, k: i32) -> i32 {\n\n }\n}",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec kth_smallest(Root :: #tree_node{} | null, K :: integer()) -> integer().\nkth_smallest(Root, K) ->\n .",
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"langSlug": "elixir",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec kth_smallest(root :: TreeNode.t | nil, k :: integer) :: integer\n def kth_smallest(root, k) do\n \n end\nend",
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"hints": [
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"Try to utilize the property of a BST.",
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"Try in-order traversal. (Credits to @chan13)",
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"What if you could modify the BST node's structure?",
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"The optimal runtime complexity is O(height of BST)."
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],
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