leetcode-problemset/leetcode-cn/originData/image-overlap.json

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            "categoryTitle": "Algorithms",
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            "title": "Image Overlap",
            "titleSlug": "image-overlap",
            "content": "<p>You are given two images, <code>img1</code> and <code>img2</code>, represented as binary, square matrices of size <code>n x n</code>. A binary matrix has only <code>0</code>s and <code>1</code>s as values.</p>\n\n<p>We <strong>translate</strong> one image however we choose by sliding all the <code>1</code> bits left, right, up, and/or down any number of units. We then place it on top of the other image. We can then calculate the <strong>overlap</strong> by counting the number of positions that have a <code>1</code> in <strong>both</strong> images.</p>\n\n<p>Note also that a translation does <strong>not</strong> include any kind of rotation. Any <code>1</code> bits that are translated outside of the matrix borders are erased.</p>\n\n<p>Return <em>the largest possible overlap</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/09/overlap1.jpg\" style=\"width: 450px; height: 231px;\" />\n<pre>\n<strong>Input:</strong> img1 = [[1,1,0],[0,1,0],[0,1,0]], img2 = [[0,0,0],[0,1,1],[0,0,1]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We translate img1 to right by 1 unit and down by 1 unit.\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/09/overlap_step1.jpg\" style=\"width: 450px; height: 105px;\" />\nThe number of positions that have a 1 in both images is 3 (shown in red).\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/09/overlap_step2.jpg\" style=\"width: 450px; height: 231px;\" />\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> img1 = [[1]], img2 = [[1]]\n<strong>Output:</strong> 1\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> img1 = [[0]], img2 = [[0]]\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == img1.length == img1[i].length</code></li>\n\t<li><code>n == img2.length == img2[i].length</code></li>\n\t<li><code>1 &lt;= n &lt;= 30</code></li>\n\t<li><code>img1[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n\t<li><code>img2[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n</ul>\n",
            "translatedTitle": "图像重叠",
            "translatedContent": "<p>给你两个图像 <code>img1</code> 和 <code>img2</code> ，两个图像的大小都是 <code>n x n</code> ，用大小相同的二进制正方形矩阵表示。二进制矩阵仅由若干 <code>0</code> 和若干 <code>1</code> 组成。</p>\n\n<p><strong>转换</strong> 其中一个图像，将所有的 <code>1</code> 向左，右，上，或下滑动任何数量的单位；然后把它放在另一个图像的上面。该转换的 <strong>重叠</strong> 是指两个图像 <strong>都</strong> 具有 <code>1</code> 的位置的数目。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p>请注意，转换 <strong>不包括</strong> 向任何方向旋转。越过矩阵边界的 <code>1</code> 都将被清除。</p>\n\n<p>最大可能的重叠数量是多少？</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/09/overlap1.jpg\" style=\"width: 450px; height: 231px;\" />\n<pre>\n<strong>输入：</strong>img1 = [[1,1,0],[0,1,0],[0,1,0]], img2 = [[0,0,0],[0,1,1],[0,0,1]]\n<strong>输出：</strong>3\n<strong>解释：</strong>将 img1 向右移动 1 个单位，再向下移动 1 个单位。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/09/overlap_step1.jpg\" style=\"width: 450px; height: 105px;\" />\n两个图像都具有 <code>1</code> 的位置的数目是 3（用红色标识）。\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/09/overlap_step2.jpg\" style=\"width: 450px; height: 231px;\" />\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>img1 = [[1]], img2 = [[1]]\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>img1 = [[0]], img2 = [[0]]\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == img1.length == img1[i].length</code></li>\n\t<li><code>n == img2.length == img2[i].length</code></li>\n\t<li><code>1 &lt;= n &lt;= 30</code></li>\n\t<li><code>img1[i][j]</code> 为 <code>0</code> 或 <code>1</code></li>\n\t<li><code>img2[i][j]</code> 为 <code>0</code> 或 <code>1</code></li>\n</ul>\n</div>\n</div>\n",
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