leetcode-problemset/leetcode-cn/originData/flipping-an-image.json

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            "questionId": "861",
            "questionFrontendId": "832",
            "categoryTitle": "Algorithms",
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            "title": "Flipping an Image",
            "titleSlug": "flipping-an-image",
            "content": "<p>Given an <code>n x n</code> binary matrix <code>image</code>, flip the image <strong>horizontally</strong>, then invert it, and return <em>the resulting image</em>.</p>\n\n<p>To flip an image horizontally means that each row of the image is reversed.</p>\n\n<ul>\n\t<li>For example, flipping <code>[1,1,0]</code> horizontally results in <code>[0,1,1]</code>.</li>\n</ul>\n\n<p>To invert an image means that each <code>0</code> is replaced by <code>1</code>, and each <code>1</code> is replaced by <code>0</code>.</p>\n\n<ul>\n\t<li>For example, inverting <code>[0,1,1]</code> results in <code>[1,0,0]</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> image = [[1,1,0],[1,0,1],[0,0,0]]\n<strong>Output:</strong> [[1,0,0],[0,1,0],[1,1,1]]\n<strong>Explanation:</strong> First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].\nThen, invert the image: [[1,0,0],[0,1,0],[1,1,1]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]\n<strong>Output:</strong> [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]\n<strong>Explanation:</strong> First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].\nThen invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == image.length</code></li>\n\t<li><code>n == image[i].length</code></li>\n\t<li><code>1 &lt;= n &lt;= 20</code></li>\n\t<li><code>images[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n</ul>\n",
            "translatedTitle": "翻转图像",
            "translatedContent": "<p>给定一个<meta charset=\"UTF-8\" />&nbsp;<code>n x n</code>&nbsp;的二进制矩阵&nbsp;<code>image</code>&nbsp;，先 <strong>水平</strong> 翻转图像，然后&nbsp;<strong>反转&nbsp;</strong>图像并返回&nbsp;<em>结果</em>&nbsp;。</p>\n\n<p><strong>水平</strong>翻转图片就是将图片的每一行都进行翻转，即逆序。</p>\n\n<ul>\n\t<li>例如，水平翻转&nbsp;<code>[1,1,0]</code>&nbsp;的结果是&nbsp;<code>[0,1,1]</code>。</li>\n</ul>\n\n<p><strong>反转</strong>图片的意思是图片中的&nbsp;<code>0</code>&nbsp;全部被&nbsp;<code>1</code>&nbsp;替换，&nbsp;<code>1</code>&nbsp;全部被&nbsp;<code>0</code>&nbsp;替换。</p>\n\n<ul>\n\t<li>例如，反转&nbsp;<code>[0,1,1]</code>&nbsp;的结果是&nbsp;<code>[1,0,0]</code>。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>image = [[1,1,0],[1,0,1],[0,0,0]]\n<strong>输出：</strong>[[1,0,0],[0,1,0],[1,1,1]]\n<strong>解释：</strong>首先翻转每一行: [[0,1,1],[1,0,1],[0,0,0]]；\n     然后反转图片: [[1,0,0],[0,1,0],[1,1,1]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]\n<strong>输出：</strong>[[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]\n<strong>解释：</strong>首先翻转每一行: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]；\n     然后反转图片: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<p><meta charset=\"UTF-8\" /></p>\n\n<ul>\n\t<li><code>n == image.length</code></li>\n\t<li><code>n == image[i].length</code></li>\n\t<li><code>1 &lt;= n &lt;= 20</code></li>\n\t<li><code>images[i][j]</code>&nbsp;==&nbsp;<code>0</code>&nbsp;或&nbsp;<code>1</code>.</li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def flipAndInvertImage(self, image):\n        \"\"\"\n        :type image: List[List[int]]\n        :rtype: List[List[int]]\n        \"\"\"",
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                    "code": "/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** flipAndInvertImage(int** image, int imageSize, int* imageColSize, int* returnSize, int** returnColumnSizes) {\n    \n}",
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