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leetcode-problemset/leetcode-cn/originData/first-letter-to-appear-twice.json

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"data": {
"question": {
"questionId": "2427",
"questionFrontendId": "2351",
"categoryTitle": "Algorithms",
"boundTopicId": 1689345,
"title": "First Letter to Appear Twice",
"titleSlug": "first-letter-to-appear-twice",
"content": "<p>Given a string <code>s</code> consisting of lowercase English letters, return <em>the first letter to appear <strong>twice</strong></em>.</p>\n\n<p><strong>Note</strong>:</p>\n\n<ul>\n\t<li>A letter <code>a</code> appears twice before another letter <code>b</code> if the <strong>second</strong> occurrence of <code>a</code> is before the <strong>second</strong> occurrence of <code>b</code>.</li>\n\t<li><code>s</code> will contain at least one letter that appears twice.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abccbaacz&quot;\n<strong>Output:</strong> &quot;c&quot;\n<strong>Explanation:</strong>\nThe letter &#39;a&#39; appears on the indexes 0, 5 and 6.\nThe letter &#39;b&#39; appears on the indexes 1 and 4.\nThe letter &#39;c&#39; appears on the indexes 2, 3 and 7.\nThe letter &#39;z&#39; appears on the index 8.\nThe letter &#39;c&#39; is the first letter to appear twice, because out of all the letters the index of its second occurrence is the smallest.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcdd&quot;\n<strong>Output:</strong> &quot;d&quot;\n<strong>Explanation:</strong>\nThe only letter that appears twice is &#39;d&#39; so we return &#39;d&#39;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n\t<li><code>s</code> has at least one repeated letter.</li>\n</ul>\n",
"translatedTitle": "第一个出现两次的字母",
"translatedContent": "<p>给你一个由小写英文字母组成的字符串 <code>s</code> ,请你找出并返回第一个出现 <strong>两次</strong> 的字母。</p>\n\n<p><strong>注意:</strong></p>\n\n<ul>\n\t<li>如果 <code>a</code> 的 <strong>第二次</strong> 出现比 <code>b</code> 的 <strong>第二次</strong> 出现在字符串中的位置更靠前,则认为字母 <code>a</code> 在字母 <code>b</code> 之前出现两次。</li>\n\t<li><code>s</code> 包含至少一个出现两次的字母。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入:</strong>s = \"abccbaacz\"\n<strong>输出:</strong>\"c\"\n<strong>解释:</strong>\n字母 'a' 在下标 0 、5 和 6 处出现。\n字母 'b' 在下标 1 和 4 处出现。\n字母 'c' 在下标 2 、3 和 7 处出现。\n字母 'z' 在下标 8 处出现。\n字母 'c' 是第一个出现两次的字母,因为在所有字母中,'c' 第二次出现的下标是最小的。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><strong>输入:</strong>s = \"abcdd\"\n<strong>输出:</strong>\"d\"\n<strong>解释:</strong>\n只有字母 'd' 出现两次,所以返回 'd' 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s</code> 由小写英文字母组成</li>\n\t<li><code>s</code> 包含至少一个重复字母</li>\n</ul>\n",
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"hints": [
"Iterate through the string from left to right. Keep track of the elements you have already seen in a set.",
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