mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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177 lines
22 KiB
JSON
177 lines
22 KiB
JSON
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"questionId": "1375",
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"questionFrontendId": "2217",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1366026,
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"title": "Find Palindrome With Fixed Length",
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"titleSlug": "find-palindrome-with-fixed-length",
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"content": "<p>Given an integer array <code>queries</code> and a <strong>positive</strong> integer <code>intLength</code>, return <em>an array</em> <code>answer</code> <em>where</em> <code>answer[i]</code> <em>is either the </em><code>queries[i]<sup>th</sup></code> <em>smallest <strong>positive palindrome</strong> of length</em> <code>intLength</code> <em>or</em> <code>-1</code><em> if no such palindrome exists</em>.</p>\n\n<p>A <strong>palindrome</strong> is a number that reads the same backwards and forwards. Palindromes cannot have leading zeros.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [1,2,3,4,5,90], intLength = 3\n<strong>Output:</strong> [101,111,121,131,141,999]\n<strong>Explanation:</strong>\nThe first few palindromes of length 3 are:\n101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, ...\nThe 90<sup>th</sup> palindrome of length 3 is 999.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [2,4,6], intLength = 4\n<strong>Output:</strong> [1111,1331,1551]\n<strong>Explanation:</strong>\nThe first six palindromes of length 4 are:\n1001, 1111, 1221, 1331, 1441, and 1551.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= queries.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 <= queries[i] <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= intLength <= 15</code></li>\n</ul>\n",
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"translatedTitle": "找到指定长度的回文数",
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"translatedContent": "<p>给你一个整数数组 <code>queries</code> 和一个 <strong>正</strong> 整数 <code>intLength</code> ，请你返回一个数组 <code>answer</code> ，其中 <code>answer[i]</code> 是长度为 <code>intLength</code> 的 <strong>正回文数</strong> 中第<em> </em><code>queries[i]</code> 小的数字，如果不存在这样的回文数，则为 <code>-1</code> 。</p>\n\n<p><strong>回文数</strong> 指的是从前往后和从后往前读一模一样的数字。回文数不能有前导 0 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>queries = [1,2,3,4,5,90], intLength = 3\n<b>输出：</b>[101,111,121,131,141,999]\n<strong>解释：</strong>\n长度为 3 的最小回文数依次是：\n101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, ...\n第 90 个长度为 3 的回文数是 999 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>queries = [2,4,6], intLength = 4\n<b>输出：</b>[1111,1331,1551]\n<strong>解释：</strong>\n长度为 4 的前 6 个回文数是：\n1001, 1111, 1221, 1331, 1441 和 1551 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= queries.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 <= queries[i] <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= intLength <= 15</code></li>\n</ul>\n",
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"code": "# @param {Integer[]} queries\n# @param {Integer} int_length\n# @return {Integer[]}\ndef kth_palindrome(queries, int_length)\n\nend",
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"For any value of queries[i] and intLength, how can you check if there exists at least queries[i] palindromes of length intLength?",
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"Since a palindrome reads the same forwards and backwards, consider how you can efficiently find the first half (ceil(intLength/2) digits) of the palindrome."
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