leetcode-problemset/leetcode-cn/originData/find-mode-in-binary-search-tree.json

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        "question": {
            "questionId": "501",
            "questionFrontendId": "501",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1712,
            "title": "Find Mode in Binary Search Tree",
            "titleSlug": "find-mode-in-binary-search-tree",
            "content": "<p>Given the <code>root</code> of a binary search tree (BST) with duplicates, return <em>all the <a href=\"https://en.wikipedia.org/wiki/Mode_(statistics)\" target=\"_blank\">mode(s)</a> (i.e., the most frequently occurred element) in it</em>.</p>\n\n<p>If the tree has more than one mode, return them in <strong>any order</strong>.</p>\n\n<p>Assume a BST is defined as follows:</p>\n\n<ul>\n\t<li>The left subtree of a node contains only nodes with keys <strong>less than or equal to</strong> the node&#39;s key.</li>\n\t<li>The right subtree of a node contains only nodes with keys <strong>greater than or equal to</strong> the node&#39;s key.</li>\n\t<li>Both the left and right subtrees must also be binary search trees.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/11/mode-tree.jpg\" style=\"width: 142px; height: 222px;\" />\n<pre>\n<strong>Input:</strong> root = [1,null,2,2]\n<strong>Output:</strong> [2]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [0]\n<strong>Output:</strong> [0]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>5</sup> &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>Follow up:</strong> Could you do that without using any extra space? (Assume that the implicit stack space incurred due to recursion does not count).",
            "translatedTitle": "二叉搜索树中的众数",
            "translatedContent": "<p>给你一个含重复值的二叉搜索树（BST）的根节点 <code>root</code> ，找出并返回 BST 中的所有 <a href=\"https://baike.baidu.com/item/%E4%BC%97%E6%95%B0/44796\" target=\"_blank\">众数</a>（即，出现频率最高的元素）。</p>\n\n<p>如果树中有不止一个众数，可以按 <strong>任意顺序</strong> 返回。</p>\n\n<p>假定 BST 满足如下定义：</p>\n\n<ul>\n\t<li>结点左子树中所含节点的值 <strong>小于等于</strong> 当前节点的值</li>\n\t<li>结点右子树中所含节点的值 <strong>大于等于</strong> 当前节点的值</li>\n\t<li>左子树和右子树都是二叉搜索树</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/11/mode-tree.jpg\" style=\"width: 142px; height: 222px;\" />\n<pre>\n<strong>输入：</strong>root = [1,null,2,2]\n<strong>输出：</strong>[2]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [0]\n<strong>输出：</strong>[0]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点的数目在范围 <code>[1, 10<sup>4</sup>]</code> 内</li>\n\t<li><code>-10<sup>5</sup> &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>你可以不使用额外的空间吗？（假设由递归产生的隐式调用栈的开销不被计算在内）</p>\n",
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                    "name": "Tree",
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                    "lang": "C++",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n    vector<int> findMode(TreeNode* root) {\n\n    }\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     int val;\n *     TreeNode left;\n *     TreeNode right;\n *     TreeNode() {}\n *     TreeNode(int val) { this.val = val; }\n *     TreeNode(int val, TreeNode left, TreeNode right) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\nclass Solution {\n    public int[] findMode(TreeNode root) {\n\n    }\n}",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode(object):\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution(object):\n    def findMode(self, root):\n        \"\"\"\n        :type root: TreeNode\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode:\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution:\n    def findMode(self, root: Optional[TreeNode]) -> List[int]:",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     struct TreeNode *left;\n *     struct TreeNode *right;\n * };\n */\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* findMode(struct TreeNode* root, int* returnSize) {\n    \n}",
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                    "lang": "C#",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public int val;\n *     public TreeNode left;\n *     public TreeNode right;\n *     public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\npublic class Solution {\n    public int[] FindMode(TreeNode root) {\n\n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.left = (left===undefined ? null : left)\n *     this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number[]}\n */\nvar findMode = function(root) {\n\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction findMode(root: TreeNode | null): number[] {\n    \n};",
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                    "lang": "PHP",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     public $val = null;\n *     public $left = null;\n *     public $right = null;\n *     function __construct($val = 0, $left = null, $right = null) {\n *         $this->val = $val;\n *         $this->left = $left;\n *         $this->right = $right;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param TreeNode $root\n     * @return Integer[]\n     */\n    function findMode($root) {\n\n    }\n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public var val: Int\n *     public var left: TreeNode?\n *     public var right: TreeNode?\n *     public init() { self.val = 0; self.left = nil; self.right = nil; }\n *     public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n *     public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n *         self.val = val\n *         self.left = left\n *         self.right = right\n *     }\n * }\n */\nclass Solution {\n    func findMode(_ root: TreeNode?) -> [Int] {\n\n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n *     var left: TreeNode? = null\n *     var right: TreeNode? = null\n * }\n */\nclass Solution {\n    fun findMode(root: TreeNode?): IntArray {\n\n    }\n}",
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                    "lang": "Dart",
                    "langSlug": "dart",
                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *   int val;\n *   TreeNode? left;\n *   TreeNode? right;\n *   TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n  List<int> findMode(TreeNode? root) {\n    \n  }\n}",
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                    "lang": "Go",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\nfunc findMode(root *TreeNode) []int {\n\n}",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode\n#     attr_accessor :val, :left, :right\n#     def initialize(val = 0, left = nil, right = nil)\n#         @val = val\n#         @left = left\n#         @right = right\n#     end\n# end\n# @param {TreeNode} root\n# @return {Integer[]}\ndef find_mode(root)\n\nend",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n *   var value: Int = _value\n *   var left: TreeNode = _left\n *   var right: TreeNode = _right\n * }\n */\nobject Solution {\n    def findMode(root: TreeNode): Array[Int] = {\n\n    }\n}",
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                    "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n//   pub val: i32,\n//   pub left: Option<Rc<RefCell<TreeNode>>>,\n//   pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n//   #[inline]\n//   pub fn new(val: i32) -> Self {\n//     TreeNode {\n//       val,\n//       left: None,\n//       right: None\n//     }\n//   }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n    pub fn find_mode(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<i32> {\n\n    }\n}",
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                    "lang": "Racket",
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                    "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n  (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n  (tree-node val #f #f))\n\n|#\n\n(define/contract (find-mode root)\n  (-> (or/c tree-node? #f) (listof exact-integer?))\n  )",
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                    "lang": "Erlang",
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                    "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%%                     left = null  :: 'null' | #tree_node{},\n%%                     right = null :: 'null' | #tree_node{}}).\n\n-spec find_mode(Root :: #tree_node{} | null) -> [integer()].\nfind_mode(Root) ->\n  .",
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                    "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           left: TreeNode.t() | nil,\n#           right: TreeNode.t() | nil\n#         }\n#   defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n  @spec find_mode(root :: TreeNode.t | nil) :: [integer]\n  def find_mode(root) do\n    \n  end\nend",
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