mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
28 KiB
JSON
186 lines
28 KiB
JSON
{
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"questionId": "652",
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"questionFrontendId": "652",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1713,
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"title": "Find Duplicate Subtrees",
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"titleSlug": "find-duplicate-subtrees",
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"content": "<p>Given the <code>root</code> of a binary tree, return all <strong>duplicate subtrees</strong>.</p>\n\n<p>For each kind of duplicate subtrees, you only need to return the root node of any <b>one</b> of them.</p>\n\n<p>Two trees are <strong>duplicate</strong> if they have the <strong>same structure</strong> with the <strong>same node values</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/16/e1.jpg\" style=\"width: 450px; height: 354px;\" />\n<pre>\n<strong>Input:</strong> root = [1,2,3,4,null,2,4,null,null,4]\n<strong>Output:</strong> [[2,4],[4]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/16/e2.jpg\" style=\"width: 321px; height: 201px;\" />\n<pre>\n<strong>Input:</strong> root = [2,1,1]\n<strong>Output:</strong> [[1]]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/16/e33.jpg\" style=\"width: 450px; height: 303px;\" />\n<pre>\n<strong>Input:</strong> root = [2,2,2,3,null,3,null]\n<strong>Output:</strong> [[2,3],[3]]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of the nodes in the tree will be in the range <code>[1, 5000]</code></li>\n\t<li><code>-200 <= Node.val <= 200</code></li>\n</ul>\n",
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"translatedTitle": "寻找重复的子树",
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"translatedContent": "<p>给你一棵二叉树的根节点 <code>root</code> ，返回所有 <strong>重复的子树 </strong>。</p>\n\n<p>对于同一类的重复子树，你只需要返回其中任意 <strong>一棵 </strong>的根结点即可。</p>\n\n<p>如果两棵树具有<strong> 相同的结构</strong> 和 <strong>相同的结点值 </strong>，则认为二者是 <strong>重复 </strong>的。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/16/e1.jpg\" style=\"height: 236px; width: 300px;\" /></p>\n\n<pre>\n<strong>输入：</strong>root = [1,2,3,4,null,2,4,null,null,4]\n<strong>输出：</strong>[[2,4],[4]]</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/16/e2.jpg\" style=\"height: 125px; width: 200px;\" /></p>\n\n<pre>\n<strong>输入：</strong>root = [2,1,1]\n<strong>输出：</strong>[[1]]</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/08/16/e33.jpg\" style=\"height: 202px; width: 300px;\" /></strong></p>\n\n<pre>\n<strong>输入：</strong>root = [2,2,2,3,null,3,null]\n<strong>输出：</strong>[[2,3],[3]]</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的结点数在 <code>[1, 5000]</code> 范围内。</li>\n\t<li><code>-200 <= Node.val <= 200</code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public IList<TreeNode> FindDuplicateSubtrees(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return TreeNode[]\n */\n function findDuplicateSubtrees($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func findDuplicateSubtrees(_ root: TreeNode?) -> [TreeNode?] {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {TreeNode[]}\ndef find_duplicate_subtrees(root)\n\nend",
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