leetcode-problemset/leetcode-cn/originData/find-champion-ii.json

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        "question": {
            "questionId": "3189",
            "questionFrontendId": "2924",
            "categoryTitle": "Algorithms",
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            "title": "Find Champion II",
            "titleSlug": "find-champion-ii",
            "content": "<p>There are <code>n</code> teams numbered from <code>0</code> to <code>n - 1</code> in a tournament; each team is also a node in a <strong>DAG</strong>.</p>\n\n<p>You are given the integer <code>n</code> and a <strong>0-indexed</strong> 2D integer array <code>edges</code> of length <code><font face=\"monospace\">m</font></code> representing the <strong>DAG</strong>, where <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> indicates that there is a directed edge from team <code>u<sub>i</sub></code> to team <code>v<sub>i</sub></code> in the graph.</p>\n\n<p>A directed edge from <code>a</code> to <code>b</code> in the graph means that team <code>a</code> is <strong>stronger</strong> than team <code>b</code> and team <code>b</code> is <strong>weaker</strong> than team <code>a</code>.</p>\n\n<p>Team <code>a</code> will be the <strong>champion</strong> of the tournament if there is no team <code>b</code> that is <strong>stronger</strong> than team <code>a</code>.</p>\n\n<p>Return <em>the team that will be the <strong>champion</strong> of the tournament if there is a <strong>unique</strong> champion, otherwise, return </em><code>-1</code><em>.</em></p>\n\n<p><strong>Notes</strong></p>\n\n<ul>\n\t<li>A <strong>cycle</strong> is a series of nodes <code>a<sub>1</sub>, a<sub>2</sub>, ..., a<sub>n</sub>, a<sub>n+1</sub></code> such that node <code>a<sub>1</sub></code> is the same node as node <code>a<sub>n+1</sub></code>, the nodes <code>a<sub>1</sub>, a<sub>2</sub>, ..., a<sub>n</sub></code> are distinct, and there is a directed edge from the node <code>a<sub>i</sub></code> to node <code>a<sub>i+1</sub></code> for every <code>i</code> in the range <code>[1, n]</code>.</li>\n\t<li>A <strong>DAG</strong> is a directed graph that does not have any <strong>cycle</strong>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><img height=\"300\" src=\"https://assets.leetcode.com/uploads/2023/10/19/graph-3.png\" width=\"300\" /></p>\n\n<pre>\n<strong>Input:</strong> n = 3, edges = [[0,1],[1,2]]\n<strong>Output:</strong> 0\n<strong>Explanation: </strong>Team 1 is weaker than team 0. Team 2 is weaker than team 1. So the champion is team 0.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<p><img height=\"300\" src=\"https://assets.leetcode.com/uploads/2023/10/19/graph-4.png\" width=\"300\" /></p>\n\n<pre>\n<strong>Input:</strong> n = 4, edges = [[0,2],[1,3],[1,2]]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> Team 2 is weaker than team 0 and team 1. Team 3 is weaker than team 1. But team 1 and team 0 are not weaker than any other teams. So the answer is -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>m == edges.length</code></li>\n\t<li><code>0 &lt;= m &lt;= n * (n - 1) / 2</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edge[i][j] &lt;= n - 1</code></li>\n\t<li><code>edges[i][0] != edges[i][1]</code></li>\n\t<li>The input is generated such that if team <code>a</code> is stronger than team <code>b</code>, team <code>b</code> is not stronger than team <code>a</code>.</li>\n\t<li>The input is generated such that if team <code>a</code> is stronger than team <code>b</code> and team <code>b</code> is stronger than team <code>c</code>, then team <code>a</code> is stronger than team <code>c</code>.</li>\n</ul>\n",
            "translatedTitle": "找到冠军 II",
            "translatedContent": "<p>一场比赛中共有 <code>n</code> 支队伍，按从 <code>0</code> 到&nbsp; <code>n - 1</code> 编号。每支队伍也是 <strong>有向无环图（DAG）</strong> 上的一个节点。</p>\n\n<p>给你一个整数 <code>n</code> 和一个下标从 <strong>0</strong> 开始、长度为 <code>m</code> 的二维整数数组 <code>edges</code> 表示这个有向无环图，其中 <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> 表示图中存在一条从 <code>u<sub>i</sub></code> 队到 <code>v<sub>i</sub></code> 队的有向边。</p>\n\n<p>从 <code>a</code> 队到 <code>b</code> 队的有向边意味着 <code>a</code> 队比 <code>b</code> 队 <strong>强</strong> ，也就是 <code>b</code> 队比 <code>a</code> 队 <strong>弱</strong> 。</p>\n\n<p>在这场比赛中，如果不存在某支强于 <code>a</code> 队的队伍，则认为 <code>a</code> 队将会是 <strong>冠军</strong> 。</p>\n\n<p>如果这场比赛存在 <strong>唯一</strong> 一个冠军，则返回将会成为冠军的队伍。否则，返回<em> </em><code>-1</code><em> 。</em></p>\n\n<p><strong>注意</strong></p>\n\n<ul>\n\t<li><strong>环</strong> 是形如 <code>a<sub>1</sub>, a<sub>2</sub>, ..., a<sub>n</sub>, a<sub>n+1</sub></code> 的一个序列，且满足：节点 <code>a<sub>1</sub></code> 与节点 <code>a<sub>n+1</sub></code> 是同一个节点；节点 <code>a<sub>1</sub>, a<sub>2</sub>, ..., a<sub>n</sub></code> 互不相同；对于范围&nbsp;<code>[1, n]</code> 中的每个 <code>i</code> ，均存在一条从节点 <code>a<sub>i</sub></code> 到节点 <code>a<sub>i+1</sub></code> 的有向边。</li>\n\t<li><strong>有向无环图</strong> 是不存在任何环的有向图。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<p><img height=\"300\" src=\"https://assets.leetcode.com/uploads/2023/10/19/graph-3.png\" width=\"300\" /></p>\n\n<pre>\n<strong>输入：</strong>n = 3, edges = [[0,1],[1,2]]\n<strong>输出：</strong>0\n<strong>解释：</strong>1 队比 0 队弱。2 队比 1 队弱。所以冠军是 0 队。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<p><img height=\"300\" src=\"https://assets.leetcode.com/uploads/2023/10/19/graph-4.png\" width=\"300\" /></p>\n\n<pre>\n<strong>输入：</strong>n = 4, edges = [[0,2],[1,3],[1,2]]\n<strong>输出：</strong>-1\n<strong>解释：</strong>2 队比 0 队和 1 队弱。3 队比 1 队弱。但是 1 队和 0 队之间不存在强弱对比。所以答案是 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>m == edges.length</code></li>\n\t<li><code>0 &lt;= m &lt;= n * (n - 1) / 2</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edge[i][j] &lt;= n - 1</code></li>\n\t<li><code>edges[i][0] != edges[i][1]</code></li>\n\t<li>生成的输入满足：如果 <code>a</code> 队比 <code>b</code> 队强，就不存在 <code>b</code> 队比 <code>a</code> 队强</li>\n\t<li>生成的输入满足：如果 <code>a</code> 队比 <code>b</code> 队强，<code>b</code> 队比 <code>c</code> 队强，那么 <code>a</code> 队比 <code>c</code> 队强</li>\n</ul>\n",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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