leetcode-problemset/leetcode-cn/originData/find-all-lonely-numbers-in-the-array.json

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        "question": {
            "questionId": "2270",
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            "categoryTitle": "Algorithms",
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            "title": "Find All Lonely Numbers in the Array",
            "titleSlug": "find-all-lonely-numbers-in-the-array",
            "content": "<p>You are given an integer array <code>nums</code>. A number <code>x</code> is <strong>lonely</strong> when it appears only <strong>once</strong>, and no <strong>adjacent</strong> numbers (i.e. <code>x + 1</code> and <code>x - 1)</code> appear in the array.</p>\n\n<p>Return <em><strong>all</strong> lonely numbers in </em><code>nums</code>. You may return the answer in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,6,5,8]\n<strong>Output:</strong> [10,8]\n<strong>Explanation:</strong> \n- 10 is a lonely number since it appears exactly once and 9 and 11 does not appear in nums.\n- 8 is a lonely number since it appears exactly once and 7 and 9 does not appear in nums.\n- 5 is not a lonely number since 6 appears in nums and vice versa.\nHence, the lonely numbers in nums are [10, 8].\nNote that [8, 10] may also be returned.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,5,3]\n<strong>Output:</strong> [1,5]\n<strong>Explanation:</strong> \n- 1 is a lonely number since it appears exactly once and 0 and 2 does not appear in nums.\n- 5 is a lonely number since it appears exactly once and 4 and 6 does not appear in nums.\n- 3 is not a lonely number since it appears twice.\nHence, the lonely numbers in nums are [1, 5].\nNote that [5, 1] may also be returned.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "找出数组中的所有孤独数字",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> 。如果数字 <code>x</code> 在数组中仅出现 <strong>一次</strong> ，且没有 <strong>相邻</strong> 数字（即，<code>x + 1</code> 和 <code>x - 1</code>）出现在数组中，则认为数字 <code>x</code> 是 <strong>孤独数字</strong> 。</p>\n\n<p>返回<em> </em><code>nums</code> 中的 <strong>所有</strong> 孤独数字。你可以按 <strong>任何顺序</strong> 返回答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [10,6,5,8]\n<strong>输出：</strong>[10,8]\n<strong>解释：</strong>\n- 10 是一个孤独数字，因为它只出现一次，并且 9 和 11 没有在 nums 中出现。\n- 8 是一个孤独数字，因为它只出现一次，并且 7 和 9 没有在 nums 中出现。\n- 5 不是一个孤独数字，因为 6 出现在 nums 中，反之亦然。\n因此，nums 中的孤独数字是 [10, 8] 。\n注意，也可以返回 [8, 10] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,3,5,3]\n<strong>输出：</strong>[1,5]\n<strong>解释：</strong>\n- 1 是一个孤独数字，因为它只出现一次，并且 0 和 2 没有在 nums 中出现。\n- 5 是一个孤独数字，因为它只出现一次，并且 4 和 6 没有在 nums 中出现。\n- 3 不是一个孤独数字，因为它出现两次。\n因此，nums 中的孤独数字是 [1, 5] 。\n注意，也可以返回 [5, 1] 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<int> findLonely(vector<int>& nums) {\n        \n    }\n};",
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                "For a given element x, how can you quickly check if x - 1 and x + 1 are present in the array without reiterating through the entire array?",
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