leetcode-problemset/leetcode-cn/originData/factorial-zeros-lcci.json

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        "question": {
            "questionId": "1000017",
            "questionFrontendId": "面试题 16.05",
            "categoryTitle": "LCCI",
            "boundTopicId": 92948,
            "title": "Factorial Zeros LCCI",
            "titleSlug": "factorial-zeros-lcci",
            "content": "<p>Write an algorithm which computes the number of trailing zeros in n factorial.</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> 3\r\n<strong>Output:</strong> 0\r\n<strong>Explanation:</strong>&nbsp;3! = 6, no trailing zero.</pre>\r\n\r\n<p><strong>Example&nbsp;2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> 5\r\n<strong>Output:</strong> 1\r\n<strong>Explanation:</strong>&nbsp;5! = 120, one trailing zero.</pre>\r\n\r\n<p><b>Note:&nbsp;</b>Your solution should be in logarithmic time complexity.</p>\r\n",
            "translatedTitle": "阶乘尾数",
            "translatedContent": "<p>设计一个算法，算出 n 阶乘有多少个尾随零。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:</strong> 3\n<strong>输出:</strong> 0\n<strong>解释:</strong>&nbsp;3! = 6, 尾数中没有零。</pre>\n\n<p><strong>示例&nbsp;2:</strong></p>\n\n<pre><strong>输入:</strong> 5\n<strong>输出:</strong> 1\n<strong>解释:</strong>&nbsp;5! = 120, 尾数中有 1 个零.</pre>\n\n<p><strong>说明: </strong>你算法的时间复杂度应为&nbsp;<em>O</em>(log&nbsp;<em>n</em>)<em>&nbsp;</em>。</p>\n",
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            "difficulty": "Easy",
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                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    int trailingZeroes(int n) {\n\n    }\n};",
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                    "code": "class Solution {\n    public int trailingZeroes(int n) {\n\n    }\n}",
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                },
                {
                    "lang": "Python",
                    "langSlug": "python",
                    "code": "class Solution(object):\n    def trailingZeroes(self, n):\n        \"\"\"\n        :type n: int\n        :rtype: int\n        \"\"\"",
                    "__typename": "CodeSnippetNode"
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                    "code": "class Solution:\n    def trailingZeroes(self, n: int) -> int:",
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                    "code": "\n\nint trailingZeroes(int n){\n\n}\n",
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                    "code": "public class Solution {\n    public int TrailingZeroes(int n) {\n\n    }\n}",
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                    "code": "/**\n * @param {number} n\n * @return {number}\n */\nvar trailingZeroes = function(n) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $n\n     * @return Integer\n     */\n    function trailingZeroes($n) {\n\n    }\n}",
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                    "code": "class Solution {\n    func trailingZeroes(_ n: Int) -> Int {\n\n    }\n}",
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                    "lang": "Go",
                    "langSlug": "golang",
                    "code": "func trailingZeroes(n int) int {\n\n}",
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                    "code": "# @param {Integer} n\n# @return {Integer}\ndef trailing_zeroes(n)\n\nend",
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            "hints": [
                "0如何变成n!？这是什么意思？",
                "n!中的每个0表示n能被10整除一次。这是什么意思？",
                "n!中每一个因子10都意味着n!能被5和2整除。",
                "你能计算出5和2的因数的个数吗？需要两者都计算吗？",
                "你是否考虑过25实际上记录了两次因数5？"
            ],
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