leetcode-problemset/leetcode-cn/originData/diving-board-lcci.json

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        "question": {
            "questionId": "100352",
            "questionFrontendId": "面试题 16.11",
            "categoryTitle": "LCCI",
            "boundTopicId": 91295,
            "title": "Diving Board LCCI",
            "titleSlug": "diving-board-lcci",
            "content": "<p>You are building a diving board by placing a bunch of planks of wood end-to-end. There are two types of planks, one of length <code>shorter</code> and one of length <code>longer</code>. You must use exactly <code>K</code> planks of wood. Write a method to generate all possible lengths for the diving board.</p>\r\n\r\n<p>return all lengths in non-decreasing order.</p>\r\n\r\n<p><strong>Example: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>\r\nshorter = 1\r\nlonger = 2\r\nk = 3\r\n<strong>Output: </strong> {3,4,5,6}\r\n</pre>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ul>\r\n\t<li>0 &lt; shorter &lt;= longer</li>\r\n\t<li>0 &lt;= k &lt;= 100000</li>\r\n</ul>\r\n",
            "translatedTitle": "跳水板",
            "translatedContent": "<p>你正在使用一堆木板建造跳水板。有两种类型的木板，其中长度较短的木板长度为<code>shorter</code>，长度较长的木板长度为<code>longer</code>。你必须正好使用<code>k</code>块木板。编写一个方法，生成跳水板所有可能的长度。</p>\n\n<p>返回的长度需要从小到大排列。</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><code><strong>输入：</strong>\nshorter = 1\nlonger = 2\nk = 3\n<strong>输出：</strong> [3,4,5,6]\n<strong>解释：</strong>\n可以使用 3 次 shorter，得到结果 3；使用 2 次 shorter 和 1 次 longer，得到结果 4 。以此类推，得到最终结果。</code></pre>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>0 &lt; shorter &lt;= longer</li>\n\t<li>0 &lt;= k &lt;= 100000</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<int> divingBoard(int shorter, int longer, int k) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def divingBoard(self, shorter, longer, k):\n        \"\"\"\n        :type shorter: int\n        :type longer: int\n        :type k: int\n        :rtype: List[int]\n        \"\"\"",
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                    "code": "/**\n * @param {number} shorter\n * @param {number} longer\n * @param {number} k\n * @return {number[]}\n */\nvar divingBoard = function(shorter, longer, k) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $shorter\n     * @param Integer $longer\n     * @param Integer $k\n     * @return Integer[]\n     */\n    function divingBoard($shorter, $longer, $k) {\n\n    }\n}",
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                    "code": "# @param {Integer} shorter\n# @param {Integer} longer\n# @param {Integer} k\n# @return {Integer[]}\ndef diving_board(shorter, longer, k)\n\nend",
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            "hints": [
                "考虑制作一个跳水板。你的选择是什么？",
                "考虑递归解法。",
                "一旦有了递归算法，就考虑一下时间复杂度。能快点吗？如何进行？",
                " 考虑使用缓存来优化时间复杂度。仔细想想你到底需要缓存什么。时间复杂度是什么？时间复杂度与表的最大尺寸密切相关。",
                "有一个替代的、聪明的（而且非常快速的）解决方案。实际上你可以在线性时间内不用递归求解。如何进行？",
                "这样想：你选择K块木板，其有两种不同的类型。对于第一种木板选择10个、第二种木板选择4个的所有方案，它们的和都是相同的。你能遍历所有可能的选择吗？"
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