leetcode-problemset/leetcode-cn/originData/distinct-subsequences.json

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        "question": {
            "questionId": "115",
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            "categoryTitle": "Algorithms",
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            "title": "Distinct Subsequences",
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            "content": "<p>Given two strings s and t, return <i>the number of distinct</i> <b><i>subsequences</i></b><i> of </i>s<i> which equals </i>t.</p>\n\n<p>The test cases are generated so that the answer fits on a 32-bit signed integer.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;rabbbit&quot;, t = &quot;rabbit&quot;\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nAs shown below, there are 3 ways you can generate &quot;rabbit&quot; from s.\n<code><strong><u>rabb</u></strong>b<strong><u>it</u></strong></code>\n<code><strong><u>ra</u></strong>b<strong><u>bbit</u></strong></code>\n<code><strong><u>rab</u></strong>b<strong><u>bit</u></strong></code>\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;babgbag&quot;, t = &quot;bag&quot;\n<strong>Output:</strong> 5\n<strong>Explanation:</strong>\nAs shown below, there are 5 ways you can generate &quot;bag&quot; from s.\n<code><strong><u>ba</u></strong>b<u><strong>g</strong></u>bag</code>\n<code><strong><u>ba</u></strong>bgba<strong><u>g</u></strong></code>\n<code><u><strong>b</strong></u>abgb<strong><u>ag</u></strong></code>\n<code>ba<u><strong>b</strong></u>gb<u><strong>ag</strong></u></code>\n<code>babg<strong><u>bag</u></strong></code></pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 1000</code></li>\n\t<li><code>s</code> and <code>t</code> consist of English letters.</li>\n</ul>\n",
            "translatedTitle": "不同的子序列",
            "translatedContent": "<p>给你两个字符串 <code>s</code><strong> </strong>和 <code>t</code> ，统计并返回在 <code>s</code> 的 <strong>子序列</strong> 中 <code>t</code> 出现的个数，结果需要对&nbsp;10<sup>9</sup> + 7 取模。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"rabbbit\", t = \"rabbit\"<code>\n<strong>输出</strong></code><strong>：</strong><code>3\n</code><strong>解释：</strong>\n如下所示, 有 3 种可以从 s 中得到 <code>\"rabbit\" 的方案</code>。\n<code><strong><u>rabb</u></strong>b<strong><u>it</u></strong></code>\n<code><strong><u>ra</u></strong>b<strong><u>bbit</u></strong></code>\n<code><strong><u>rab</u></strong>b<strong><u>bit</u></strong></code></pre>\n\n<p><strong>示例&nbsp;2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"babgbag\", t = \"bag\"\n<code><strong>输出</strong></code><strong>：</strong><code>5\n</code><strong>解释：</strong>\n如下所示, 有 5 种可以从 s 中得到 <code>\"bag\" 的方案</code>。 \n<code><strong><u>ba</u></strong>b<u><strong>g</strong></u>bag</code>\n<code><strong><u>ba</u></strong>bgba<strong><u>g</u></strong></code>\n<code><u><strong>b</strong></u>abgb<strong><u>ag</u></strong></code>\n<code>ba<u><strong>b</strong></u>gb<u><strong>ag</strong></u></code>\n<code>babg<strong><u>bag</u></strong></code>\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 1000</code></li>\n\t<li><code>s</code> 和 <code>t</code> 由英文字母组成</li>\n</ul>\n",
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