leetcode-problemset/leetcode-cn/originData/counter-ii.json

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            "questionId": "2789",
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            "categoryTitle": "JavaScript",
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            "title": "Counter II",
            "titleSlug": "counter-ii",
            "content": "<p>Write a function&nbsp;<code>createCounter</code>. It should accept an initial integer&nbsp;<code>init</code>. It should return an object with three functions.</p>\n\n<p>The three functions are:</p>\n\n<ul>\n\t<li><code>increment()</code>&nbsp;increases&nbsp;the current value by 1 and then returns it.</li>\n\t<li><code>decrement()</code>&nbsp;reduces the current value by 1 and then returns it.</li>\n\t<li><code>reset()</code>&nbsp;sets the current value to&nbsp;<code>init</code>&nbsp;and then returns it.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> init = 5, calls = [&quot;increment&quot;,&quot;reset&quot;,&quot;decrement&quot;]\n<strong>Output:</strong> [6,5,4]\n<strong>Explanation:</strong>\nconst counter = createCounter(5);\ncounter.increment(); // 6\ncounter.reset(); // 5\ncounter.decrement(); // 4\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> init = 0, calls = [&quot;increment&quot;,&quot;increment&quot;,&quot;decrement&quot;,&quot;reset&quot;,&quot;reset&quot;]\n<strong>Output:</strong> [1,2,1,0,0]\n<strong>Explanation:</strong>\nconst counter = createCounter(0);\ncounter.increment(); // 1\ncounter.increment(); // 2\ncounter.decrement(); // 1\ncounter.reset(); // 0\ncounter.reset(); // 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>-1000 &lt;= init &lt;= 1000</code></li>\n\t<li><code>0 &lt;= calls.length &lt;= 1000</code></li>\n\t<li><code>calls[i]</code> is one of &quot;increment&quot;, &quot;decrement&quot; and&nbsp;&quot;reset&quot;</li>\n</ul>\n",
            "translatedTitle": "计数器 II",
            "translatedContent": "<p>请你写一个函数&nbsp;<code>createCounter</code>。这个函数接收一个初始的整数值 <code>init</code>。并返回一个包含三个函数的对象。</p>\n\n<p>这三个函数是：</p>\n\n<ul>\n\t<li><code>increment()</code>&nbsp;将当前值加 1 并返回。</li>\n\t<li><code>decrement()</code>&nbsp;将当前值减 1 并返回。</li>\n\t<li><code>reset()</code>&nbsp;将当前值设置为 <code>init</code> 并返回。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>init = 5, calls = [\"increment\",\"reset\",\"decrement\"]\n<strong>输出：</strong>[6,5,4]\n<strong>解释：</strong>\nconst counter = createCounter(5);\ncounter.increment(); // 6\ncounter.reset(); // 5\ncounter.decrement(); // 4\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>init = 0, calls = [\"increment\",\"increment\",\"decrement\",\"reset\",\"reset\"]\n<strong>输出：</strong>[1,2,1,0,0]\n<strong>解释：</strong>\nconst counter = createCounter(0);\ncounter.increment(); // 1\ncounter.increment(); // 2\ncounter.decrement(); // 1\ncounter.reset(); // 0\ncounter.reset(); // 0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>-1000 &lt;= init &lt;= 1000</code></li>\n\t<li><code>0 &lt;= calls.length &lt;= 1000</code></li>\n\t<li><code>calls[i]</code> 是 “increment”、“decrement” 和 “reset” 中的一个</li>\n</ul>\n",
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                    "code": "/**\n * @param {integer} init\n * @return { increment: Function, decrement: Function, reset: Function }\n */\nvar createCounter = function(init) {\n    \n};\n\n/**\n * const counter = createCounter(5)\n * counter.increment(); // 6\n * counter.reset(); // 5\n * counter.decrement(); // 4\n */",
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                    "code": "type ReturnObj = {\n    increment: () => number,\n    decrement: () => number,\n    reset: () => number,\n}\n\nfunction createCounter(init: number): ReturnObj {\n\t\n};\n\n/**\n * const counter = createCounter(5)\n * counter.increment(); // 6\n * counter.reset(); // 5\n * counter.decrement(); // 4\n */",
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            "hints": [
                "You can return an object with methods.",
                "Initialize a variable for currentCount. Inside these methods, add the appropriate logic which mutates currentCount."
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