leetcode-problemset/leetcode-cn/originData/count-number-of-bad-pairs.json

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        "question": {
            "questionId": "2448",
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            "categoryTitle": "Algorithms",
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            "title": "Count Number of Bad Pairs",
            "titleSlug": "count-number-of-bad-pairs",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>. A pair of indices <code>(i, j)</code> is a <strong>bad pair</strong> if <code>i &lt; j</code> and <code>j - i != nums[j] - nums[i]</code>.</p>\n\n<p>Return<em> the total number of <strong>bad pairs</strong> in </em><code>nums</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,1,3,3]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The pair (0, 1) is a bad pair since 1 - 0 != 1 - 4.\nThe pair (0, 2) is a bad pair since 2 - 0 != 3 - 4, 2 != -1.\nThe pair (0, 3) is a bad pair since 3 - 0 != 3 - 4, 3 != -1.\nThe pair (1, 2) is a bad pair since 2 - 1 != 3 - 1, 1 != 2.\nThe pair (2, 3) is a bad pair since 3 - 2 != 3 - 3, 1 != 0.\nThere are a total of 5 bad pairs, so we return 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There are no bad pairs.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "统计坏数对的数目",
            "translatedContent": "<p>给你一个下标从<strong>&nbsp;0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;。如果 <code>i &lt; j</code>&nbsp;且&nbsp;<code>j - i != nums[j] - nums[i]</code>&nbsp;，那么我们称&nbsp;<code>(i, j)</code>&nbsp;是一个 <strong>坏</strong><strong>数对</strong>&nbsp;。</p>\n\n<p>请你返回 <code>nums</code>&nbsp;中 <strong>坏数对</strong>&nbsp;的总数目。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [4,1,3,3]\n<b>输出：</b>5\n<b>解释：</b>数对 (0, 1) 是坏数对，因为 1 - 0 != 1 - 4 。\n数对 (0, 2) 是坏数对，因为 2 - 0 != 3 - 4, 2 != -1 。\n数对 (0, 3) 是坏数对，因为 3 - 0 != 3 - 4, 3 != -1 。\n数对 (1, 2) 是坏数对，因为 2 - 1 != 3 - 1, 1 != 2 。\n数对 (2, 3) 是坏数对，因为 3 - 2 != 3 - 3, 1 != 0 。\n总共有 5 个坏数对，所以我们返回 5 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,2,3,4,5]\n<b>输出：</b>0\n<strong>解释：</strong>没有坏数对。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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            "hints": [
                "Would it be easier to count the number of pairs that are not bad pairs?",
                "Notice that (j - i != nums[j] - nums[i]) is the same as (nums[i] - i != nums[j] - j).",
                "Keep a counter of nums[i] - i. To be efficient, use a HashMap."
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