leetcode-problemset/leetcode-cn/originData/cong-wei-dao-tou-da-yin-lian-biao-lcof.json

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        "question": {
            "questionId": "100282",
            "questionFrontendId": "LCR 123",
            "categoryTitle": "Algorithms",
            "boundTopicId": 85499,
            "title": "图书整理 I",
            "titleSlug": "cong-wei-dao-tou-da-yin-lian-biao-lcof",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\r\n",
            "translatedTitle": "图书整理 I",
            "translatedContent": "<p>书店店员有一张链表形式的书单，每个节点代表一本书，节点中的值表示书的编号。为更方便整理书架，店员需要将书单倒过来排列，就可以从最后一本书开始整理，逐一将书放回到书架上。请倒序返回这个书单链表。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>head = [3,6,4,1]\n\n<strong>输出：</strong>[1,4,6,3]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<p><code>0 &lt;= 链表长度 &lt;= 10000</code></p>\n",
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            "difficulty": "Easy",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    vector<int> reverseBookList(ListNode* head) {\n\n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public int[] reverseBookList(ListNode head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {number[]}\n */\nvar reverseBookList = function(head) {\n\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *   int val;\n *   ListNode? next;\n *   ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n  List<int> reverseBookList(ListNode? head) {\n    \n  }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc reverseBookList(head *ListNode) []int {\n\n}",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (reverse-book-list head)\n  (-> (or/c list-node? #f) (listof exact-integer?))\n  )",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec reverse_book_list(Head :: #list_node{} | null) -> [integer()].\nreverse_book_list(Head) ->\n  .",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec reverse_book_list(head :: ListNode.t | nil) :: [integer]\n  def reverse_book_list(head) do\n    \n  end\nend",
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