mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
170 lines
20 KiB
JSON
170 lines
20 KiB
JSON
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"categoryTitle": "Algorithms",
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"title": "Concatenation of Array",
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"content": "<p>Given an integer array <code>nums</code> of length <code>n</code>, you want to create an array <code>ans</code> of length <code>2n</code> where <code>ans[i] == nums[i]</code> and <code>ans[i + n] == nums[i]</code> for <code>0 <= i < n</code> (<strong>0-indexed</strong>).</p>\n\n<p>Specifically, <code>ans</code> is the <strong>concatenation</strong> of two <code>nums</code> arrays.</p>\n\n<p>Return <em>the array </em><code>ans</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,1]\n<strong>Output:</strong> [1,2,1,1,2,1]\n<strong>Explanation:</strong> The array ans is formed as follows:\n- ans = [nums[0],nums[1],nums[2],nums[0],nums[1],nums[2]]\n- ans = [1,2,1,1,2,1]</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,2,1]\n<strong>Output:</strong> [1,3,2,1,1,3,2,1]\n<strong>Explanation:</strong> The array ans is formed as follows:\n- ans = [nums[0],nums[1],nums[2],nums[3],nums[0],nums[1],nums[2],nums[3]]\n- ans = [1,3,2,1,1,3,2,1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 <= n <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 1000</code></li>\n</ul>\n",
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"translatedTitle": "数组串联",
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"translatedContent": "<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code> 。请你构建一个长度为 <code>2n</code> 的答案数组 <code>ans</code> ，数组下标<strong> 从 0 开始计数 </strong>，对于所有 <code>0 <= i < n</code> 的 <code>i</code> ，满足下述所有要求：</p>\n\n<ul>\n\t<li><code>ans[i] == nums[i]</code></li>\n\t<li><code>ans[i + n] == nums[i]</code></li>\n</ul>\n\n<p>具体而言，<code>ans</code> 由两个 <code>nums</code> 数组 <strong>串联</strong> 形成。</p>\n\n<p>返回数组<em> </em><code>ans</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,1]\n<strong>输出：</strong>[1,2,1,1,2,1]\n<strong>解释：</strong>数组 ans 按下述方式形成：\n- ans = [nums[0],nums[1],nums[2],nums[0],nums[1],nums[2]]\n- ans = [1,2,1,1,2,1]</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,3,2,1]\n<strong>输出：</strong>[1,3,2,1,1,3,2,1]\n<strong>解释：</strong>数组 ans 按下述方式形成：\n- ans = [nums[0],nums[1],nums[2],nums[3],nums[0],nums[1],nums[2],nums[3]]\n- ans = [1,3,2,1,1,3,2,1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>1 <= n <= 1000</code></li>\n\t<li><code>1 <= nums[i] <= 1000</code></li>\n</ul>\n",
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