leetcode-problemset/leetcode-cn/originData/check-if-binary-string-has-at-most-one-segment-of-ones.json

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        "question": {
            "questionId": "1910",
            "questionFrontendId": "1784",
            "categoryTitle": "Algorithms",
            "boundTopicId": 634410,
            "title": "Check if Binary String Has at Most One Segment of Ones",
            "titleSlug": "check-if-binary-string-has-at-most-one-segment-of-ones",
            "content": "<p>Given a binary string <code>s</code> <strong>​​​​​without leading zeros</strong>, return <code>true</code>​​​ <em>if </em><code>s</code><em> contains <strong>at most one contiguous segment of ones</strong></em>. Otherwise, return <code>false</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;1001&quot;\n<strong>Output:</strong> false\n<strong>Explanation: </strong>The ones do not form a contiguous segment.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;110&quot;\n<strong>Output:</strong> true</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code>​​​​ is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>\n\t<li><code>s[0]</code> is&nbsp;<code>&#39;1&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "检查二进制字符串字段",
            "translatedContent": "<p>给你一个二进制字符串 <code>s</code> ，该字符串 <strong>不含前导零</strong> 。</p>\n\n<p>如果 <code>s</code> 包含 <strong>零个或一个由连续的 <code>'1'</code> 组成的字段</strong> ，返回 <code>true</code>​​​ 。否则，返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"1001\"\n<strong>输出：</strong>false\n<strong>解释：</strong>由连续若干个&nbsp;<code>'1'</code> 组成的字段数量为 2，返回 false\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"110\"\n<strong>输出：</strong>true</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>s[i]</code>​​​​ 为 <code>'0'</code> 或 <code>'1'</code></li>\n\t<li><code>s[0]</code> 为 <code>'1'</code></li>\n</ul>\n",
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            "topicTags": [
                {
                    "name": "String",
                    "slug": "string",
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                    "code": "class Solution {\npublic:\n    bool checkOnesSegment(string s) {\n\n    }\n};",
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            "hints": [
                "It's guaranteed to have at least one segment",
                "The string size is small so you can count all segments of ones with no that have no adjacent ones."
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            "sampleTestCase": "\"1001\"",
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