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"questionId": "842",
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"categoryTitle": "Algorithms",
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"title": "Card Flipping Game",
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"content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>fronts</code> and <code>backs</code> of length <code>n</code>, where the <code>i<sup>th</sup></code> card has the positive integer <code>fronts[i]</code> printed on the front and <code>backs[i]</code> printed on the back. Initially, each card is placed on a table such that the front number is facing up and the other is facing down. You may flip over any number of cards (possibly zero).</p>\n\n<p>After flipping the cards, an integer is considered <strong>good</strong> if it is facing down on some card and <strong>not</strong> facing up on any card.</p>\n\n<p>Return <em>the minimum possible good integer after flipping the cards</em>. If there are no good integers, return <code>0</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> fronts = [1,2,4,4,7], backs = [1,3,4,1,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nIf we flip the second card, the face up numbers are [1,3,4,4,7] and the face down are [1,2,4,1,3].\n2 is the minimum good integer as it appears facing down but not facing up.\nIt can be shown that 2 is the minimum possible good integer obtainable after flipping some cards.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> fronts = [1], backs = [1]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nThere are no good integers no matter how we flip the cards, so we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == fronts.length == backs.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>1 &lt;= fronts[i], backs[i] &lt;= 2000</code></li>\n</ul>\n",
"translatedTitle": "翻转卡片游戏",
"translatedContent": "<p>在桌子上有 <code>n</code> 张卡片,每张卡片的正面和背面都写着一个正数(正面与背面上的数有可能不一样)。</p>\n\n<p>我们可以先翻转任意张卡片,然后选择其中一张卡片。</p>\n\n<p>如果选中的那张卡片背面的数字 <code>x</code> 与任意一张卡片的正面的数字都不同,那么这个数字是我们想要的数字。</p>\n\n<p>哪个数是这些想要的数字中最小的数(找到这些数中的最小值)呢?如果没有一个数字符合要求的,输出 <code>0</code> 。</p>\n\n<p>其中, <code>fronts[i]</code>&nbsp;和&nbsp;<code>backs[i]</code>&nbsp;分别代表第&nbsp;<code>i</code>&nbsp;张卡片的正面和背面的数字。</p>\n\n<p>如果我们通过翻转卡片来交换正面与背面上的数,那么当初在正面的数就变成背面的数,背面的数就变成正面的数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>fronts = [1,2,4,4,7], backs = [1,3,4,1,3]\n<strong>输出:</strong><code>2</code>\n<strong>解释:</strong>假设我们翻转第二张卡片,那么在正面的数变成了 <code>[1,3,4,4,7]</code> 背面的数变成了 <code>[1,2,4,1,3]。</code>\n接着我们选择第二张卡片因为现在该卡片的背面的数是 22 与任意卡片上正面的数都不同,所以 2 就是我们想要的数字。</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>fronts = [1], backs = [1]\n<strong>输出:</strong>0\n<strong>解释:</strong>\n无论如何翻转都无法得到想要的数字所以返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == fronts.length == backs.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>1 &lt;= fronts[i], backs[i] &lt;= 2000</code></li>\n</ul>\n",
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