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"title": "Binary Gap",
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"content": "<p>Given a positive integer <code>n</code>, find and return <em>the <strong>longest distance</strong> between any two <strong>adjacent</strong> </em><code>1</code><em>&#39;s in the binary representation of </em><code>n</code><em>. If there are no two adjacent </em><code>1</code><em>&#39;s, return </em><code>0</code><em>.</em></p>\n\n<p>Two <code>1</code>&#39;s are <strong>adjacent</strong> if there are only <code>0</code>&#39;s separating them (possibly no <code>0</code>&#39;s). The <b>distance</b> between two <code>1</code>&#39;s is the absolute difference between their bit positions. For example, the two <code>1</code>&#39;s in <code>&quot;1001&quot;</code> have a distance of 3.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 22\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> 22 in binary is &quot;10110&quot;.\nThe first adjacent pair of 1&#39;s is &quot;<u>1</u>0<u>1</u>10&quot; with a distance of 2.\nThe second adjacent pair of 1&#39;s is &quot;10<u>11</u>0&quot; with a distance of 1.\nThe answer is the largest of these two distances, which is 2.\nNote that &quot;<u>1</u>01<u>1</u>0&quot; is not a valid pair since there is a 1 separating the two 1&#39;s underlined.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 8\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> 8 in binary is &quot;1000&quot;.\nThere are not any adjacent pairs of 1&#39;s in the binary representation of 8, so we return 0.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> 5 in binary is &quot;101&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
"translatedTitle": "二进制间距",
"translatedContent": "<p>给定一个正整数 <code>n</code>,找到并返回 <code>n</code> 的二进制表示中两个 <strong>相邻</strong> 1 之间的<strong> 最长距离 </strong>。如果不存在两个相邻的 1返回 <code>0</code> 。</p>\n\n<p>如果只有 <code>0</code> 将两个 <code>1</code> 分隔开(可能不存在 <code>0</code> ),则认为这两个 1 彼此 <strong>相邻</strong> 。两个 <code>1</code> 之间的距离是它们的二进制表示中位置的绝对差。例如,<code>\"1001\"</code> 中的两个 <code>1</code> 的距离为 3 。</p>\n\n<p>&nbsp;</p>\n\n<ul>\n</ul>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 22\n<strong>输出:</strong>2\n<strong>解释:</strong>22 的二进制是 \"10110\" 。\n在 22 的二进制表示中,有三个 1组成两对相邻的 1 。\n第一对相邻的 1 中,两个 1 之间的距离为 2 。\n第二对相邻的 1 中,两个 1 之间的距离为 1 。\n答案取两个距离之中最大的也就是 2 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 8\n<strong>输出:</strong>0\n<strong>解释:</strong>8 的二进制是 \"1000\" 。\n在 8 的二进制表示中没有相邻的两个 1所以返回 0 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 5\n<strong>输出:</strong>2\n<strong>解释:</strong>5 的二进制是 \"101\" 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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