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"categoryTitle": "JavaScript",
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"title": "Array Reduce Transformation",
"titleSlug": "array-reduce-transformation",
"content": "<p>Given an integer array&nbsp;<code>nums</code>, a reducer function&nbsp;<code>fn</code>, and an initial value&nbsp;<code>init</code>, return a&nbsp;<strong>reduced</strong>&nbsp;array.</p>\n\n<p>A&nbsp;<strong>reduced</strong>&nbsp;array is created by applying the following operation:&nbsp;<code>val = fn(init, nums[0])</code>, <code>val&nbsp;= fn(val, nums[1])</code>,&nbsp;<code>val&nbsp;= fn(val, nums[2])</code>,&nbsp;<code>...</code>&nbsp;until every element in the array has been processed. The final value of&nbsp;<code>val</code>&nbsp;is returned.</p>\n\n<p>If the length of the array is 0, it should return&nbsp;<code>init</code>.</p>\n\n<p>Please solve it without using the built-in <code>Array.reduce</code> method.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nnums = [1,2,3,4]\nfn = function sum(accum, curr) { return accum + curr; }\ninit = 0\n<strong>Output:</strong> 10\n<strong>Explanation:</strong>\ninitially, the value is init=0.\n(0) + nums[0] = 1\n(1) + nums[1] = 3\n(3) + nums[2] = 6\n(6) + nums[3] = 10\nThe final answer is 10.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nnums = [1,2,3,4]\nfn = function sum(accum, curr) { return accum + curr * curr; }\ninit = 100\n<strong>Output:</strong> 130\n<strong>Explanation:</strong>\ninitially, the value is init=100.\n(100) + nums[0]^2 = 101\n(101) + nums[1]^2 = 105\n(105) + nums[2]^2 = 114\n(114) + nums[3]^2 = 130\nThe final answer is 130.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nnums = []\nfn = function sum(accum, curr) { return 0; }\ninit = 25\n<strong>Output:</strong> 25\n<strong>Explanation:</strong> For empty arrays, the answer is always init.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= init &lt;= 1000</code></li>\n</ul>\n",
"translatedTitle": "数组归约运算",
"translatedContent": "<p>请你编写一个函数,它的参数为一个整数数组&nbsp;<code>nums</code>&nbsp;、一个计算函数&nbsp;<code>fn</code>&nbsp;和初始值<code>init</code>&nbsp;。返回一个数组&nbsp;<strong>归约后 </strong>的值。</p>\n\n<p>你可以定义一个数组&nbsp;<strong>归约后 </strong>的值,然后应用以下操作: <code>val = fn(init, nums[0])</code>&nbsp; <code>val = fn(val, nums[1])</code>&nbsp; <code>val = fn(val, nums[2])</code>&nbsp;<code>...</code>&nbsp;直到数组中的每个元素都被处理完毕。返回 <code>val</code> 的最终值。</p>\n\n<p>如果数组的长度为 0它应该返回 <code>init</code>&nbsp;的值。</p>\n\n<p>请你在不使用内置数组方法的&nbsp;<code>Array.reduce</code>&nbsp;前提下解决这个问题。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>\nnums = [1,2,3,4]\nfn = function sum(accum, curr) { return accum + curr; }\ninit = 0\n<strong>输出:</strong>10\n<strong>解释:</strong>\n初始值为 init=0 。\n(0) + nums[0] = 1\n(1) + nums[1] = 3\n(3) + nums[2] = 6\n(6) + nums[3] = 10\nVal 最终值为 10。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong> \nnums = [1,2,3,4]\nfn = function sum(accum, curr) { return accum + curr * curr; }\ninit = 100\n<strong>输出:</strong>130\n<strong>解释:</strong>\n初始值为 init=100 。\n(100) + nums[0]^2 = 101\n(101) + nums[1]^2 = 105\n(105) + nums[2]^2 = 114\n(114) + nums[3]^2 = 130\nVal 最终值为 130。\n</pre>\n\n<p><strong class=\"example\">示例3:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nnums = []\nfn = function sum(accum, curr) { return 0; }\ninit = 25\n<strong>输出:</strong>25\n<b>解释:</b>这是一个空数组,所以返回 init 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>0 &lt;= init &lt;= 1000</code></li>\n</ul>\n",
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