mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
29 KiB
JSON
186 lines
29 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "623",
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"questionFrontendId": "623",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1789,
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"title": "Add One Row to Tree",
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"titleSlug": "add-one-row-to-tree",
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"content": "<p>Given the <code>root</code> of a binary tree and two integers <code>val</code> and <code>depth</code>, add a row of nodes with value <code>val</code> at the given depth <code>depth</code>.</p>\n\n<p>Note that the <code>root</code> node is at depth <code>1</code>.</p>\n\n<p>The adding rule is:</p>\n\n<ul>\n\t<li>Given the integer <code>depth</code>, for each not null tree node <code>cur</code> at the depth <code>depth - 1</code>, create two tree nodes with value <code>val</code> as <code>cur</code>'s left subtree root and right subtree root.</li>\n\t<li><code>cur</code>'s original left subtree should be the left subtree of the new left subtree root.</li>\n\t<li><code>cur</code>'s original right subtree should be the right subtree of the new right subtree root.</li>\n\t<li>If <code>depth == 1</code> that means there is no depth <code>depth - 1</code> at all, then create a tree node with value <code>val</code> as the new root of the whole original tree, and the original tree is the new root's left subtree.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/15/addrow-tree.jpg\" style=\"width: 500px; height: 231px;\" />\n<pre>\n<strong>Input:</strong> root = [4,2,6,3,1,5], val = 1, depth = 2\n<strong>Output:</strong> [4,1,1,2,null,null,6,3,1,5]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/11/add2-tree.jpg\" style=\"width: 500px; height: 277px;\" />\n<pre>\n<strong>Input:</strong> root = [4,2,null,3,1], val = 1, depth = 3\n<strong>Output:</strong> [4,2,null,1,1,3,null,null,1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li>The depth of the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n\t<li><code>-10<sup>5</sup> <= val <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= depth <= the depth of tree + 1</code></li>\n</ul>\n",
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"translatedTitle": "在二叉树中增加一行",
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"translatedContent": "<p>给定一个二叉树的根 <code>root</code> 和两个整数 <code>val</code> 和 <code>depth</code> ，在给定的深度 <code>depth</code> 处添加一个值为 <code>val</code> 的节点行。</p>\n\n<p>注意，根节点 <code>root</code> 位于深度 <code>1</code> 。</p>\n\n<p>加法规则如下:</p>\n\n<ul>\n\t<li>给定整数 <code>depth</code>，对于深度为 <code>depth - 1</code> 的每个非空树节点 <code>cur</code> ，创建两个值为 <code>val</code> 的树节点作为 <code>cur</code> 的左子树根和右子树根。</li>\n\t<li><code>cur</code> 原来的左子树应该是新的左子树根的左子树。</li>\n\t<li><code>cur</code> 原来的右子树应该是新的右子树根的右子树。</li>\n\t<li>如果 <code>depth == 1 </code>意味着 <code>depth - 1</code> 根本没有深度，那么创建一个树节点，值 <code>val </code>作为整个原始树的新根，而原始树就是新根的左子树。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/15/addrow-tree.jpg\" style=\"height: 231px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入:</strong> root = [4,2,6,3,1,5], val = 1, depth = 2\n<strong>输出:</strong> [4,1,1,2,null,null,6,3,1,5]</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/11/add2-tree.jpg\" style=\"height: 277px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入:</strong> root = [4,2,null,3,1], val = 1, depth = 3\n<strong>输出:</strong> [4,2,null,1,1,3,null,null,1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>节点数在 <code>[1, 10<sup>4</sup>]</code> 范围内</li>\n\t<li>树的深度在 <code>[1, 10<sup>4</sup>]</code>范围内</li>\n\t<li><code>-100 <= Node.val <= 100</code></li>\n\t<li><code>-10<sup>5</sup> <= val <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= depth <= the depth of tree + 1</code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* addOneRow(TreeNode* root, int val, int depth) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public TreeNode addOneRow(TreeNode root, int val, int depth) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def addOneRow(self, root, val, depth):\n \"\"\"\n :type root: TreeNode\n :type val: int\n :type depth: int\n :rtype: TreeNode\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\nstruct TreeNode* addOneRow(struct TreeNode* root, int val, int depth) {\n \n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode AddOneRow(TreeNode root, int val, int depth) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} val\n * @param {number} depth\n * @return {TreeNode}\n */\nvar addOneRow = function(root, val, depth) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction addOneRow(root: TreeNode | null, val: number, depth: number): TreeNode | null {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $val\n * @param Integer $depth\n * @return TreeNode\n */\n function addOneRow($root, $val, $depth) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func addOneRow(_ root: TreeNode?, _ val: Int, _ depth: Int) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun addOneRow(root: TreeNode?, `val`: Int, depth: Int): TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? addOneRow(TreeNode? root, int val, int depth) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc addOneRow(root *TreeNode, val int, depth int) *TreeNode {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} val\n# @param {Integer} depth\n# @return {TreeNode}\ndef add_one_row(root, val, depth)\n\nend",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec add_one_row(root :: TreeNode.t | nil, val :: integer, depth :: integer) :: TreeNode.t | nil\n def add_one_row(root, val, depth) do\n \n end\nend",
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