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leetcode-problemset/leetcode-cn/originData/WInSav.json

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{
"data": {
"question": {
"questionId": "1000442",
"questionFrontendId": "LCP 60",
"categoryTitle": "Algorithms",
"boundTopicId": 1443274,
"title": "力扣泡泡龙",
"titleSlug": "WInSav",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "力扣泡泡龙",
"translatedContent": "欢迎各位勇者来到力扣城,本次试炼主题为「力扣泡泡龙」。\n\n游戏初始状态的泡泡形如二叉树 `root`,每个节点值对应了该泡泡的分值。勇者最多可以击破一个节点泡泡,要求满足:\n- 被击破的节点泡泡 **至多** 只有一个子节点泡泡\n- 当被击破的节点泡泡有子节点泡泡时,则子节点泡泡将取代被击破泡泡的位置\n > 注:即整棵子树泡泡上移\n\n请问在击破一个节点泡泡操作或无击破操作后二叉泡泡树的最大「层和」是多少。\n\n**注意:**\n- 「层和」为同一高度的所有节点的分值之和\n\n**示例 1**\n> 输入:`root = [6,0,3,null,8]`\n>\n> 输出:`11`\n>\n> 解释:勇者的最佳方案如图所示\n>![image.png](https://pic.leetcode-cn.com/1648180809-XSWPLu-image.png){:height=\"100px\"}\n\n\n\n**示例 2**\n> 输入:`root = [5,6,2,4,null,null,1,3,5]`\n>\n> 输出:`9`\n>\n> 解释:勇者击破 6 节点,此时「层和」最大为 3+5+1 = 9\n>![image.png](https://pic.leetcode-cn.com/1648180769-TLpYop-image.png){:height=\"200px\"}\n\n\n\n**示例 3**\n> 输入:`root = [-5,1,7]`\n>\n> 输出:`8`\n>\n> 解释:勇者不击破节点,「层和」最大为 1+7 = 8\n\n\n**提示**\n- `2 <= 树中节点个数 <= 10^5`\n- `-10000 <= 树中节点的值 <= 10000`\n",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun getMaxLayerSum(root: TreeNode?): Int {\n\n }\n}",
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{
"lang": "Racket",
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