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{
"data": {
"question": {
"questionId": "1000257",
"questionFrontendId": "LCR 021",
"categoryTitle": "Algorithms",
"boundTopicId": 910260,
"title": "删除链表的倒数第 N 个结点",
"titleSlug": "SLwz0R",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "删除链表的倒数第 N 个结点",
"translatedContent": "<p>给定一个链表,删除链表的倒数第&nbsp;<code>n</code><em>&nbsp;</em>个结点,并且返回链表的头结点。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/10/03/remove_ex1.jpg\" style=\"width: 542px; height: 222px;\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [1,2,3,4,5], n = 2\n<strong>输出:</strong>[1,2,3,5]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>head = [1], n = 1\n<strong>输出:</strong>[]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>head = [1,2], n = 1\n<strong>输出:</strong>[1]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>链表中结点的数目为 <code>sz</code></li>\n\t<li><code>1 &lt;= sz &lt;= 30</code></li>\n\t<li><code>0 &lt;= Node.val &lt;= 100</code></li>\n\t<li><code>1 &lt;= n &lt;= sz</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶:</strong>能尝试使用一趟扫描实现吗?</p>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 19&nbsp;题相同:&nbsp;<a href=\"https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list/\">https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list/</a></p>\n",
"isPaidOnly": false,
"difficulty": "Medium",
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"name": "Linked List",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def removeNthFromEnd(self, head, n):\n \"\"\"\n :type head: ListNode\n :type n: int\n :rtype: ListNode\n \"\"\"",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def removeNthFromEnd(self, head: ListNode, n: int) -> ListNode:",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * struct ListNode *next;\n * };\n */\n\n\nstruct ListNode* removeNthFromEnd(struct ListNode* head, int n){\n\n}",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public int val;\n * public ListNode next;\n * public ListNode(int val=0, ListNode next=null) {\n * this.val = val;\n * this.next = next;\n * }\n * }\n */\npublic class Solution {\n public ListNode RemoveNthFromEnd(ListNode head, int n) {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @param {number} n\n * @return {ListNode}\n */\nvar removeNthFromEnd = function(head, n) {\n\n};",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n * var next: ListNode? = null\n * }\n */\nclass Solution {\n fun removeNthFromEnd(head: ListNode?, n: Int): ListNode? {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n * Val int\n * Next *ListNode\n * }\n */\nfunc removeNthFromEnd(head *ListNode, n int) *ListNode {\n\n}",
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{
"lang": "Racket",
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"code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n (list-node val #f))\n\n|#\n\n(define/contract (remove-nth-from-end head n)\n (-> (or/c list-node? #f) exact-integer? (or/c list-node? #f))\n\n )",
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"code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# next: ListNode.t() | nil\n# }\n# defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n @spec remove_nth_from_end(head :: ListNode.t | nil, n :: integer) :: ListNode.t | nil\n def remove_nth_from_end(head, n) do\n\n end\nend",
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