mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-11-04 11:43:12 +08:00
73 lines
3.7 KiB
HTML
73 lines
3.7 KiB
HTML
<p>There are <code>k</code> workers who want to move <code>n</code> boxes from the right (old) warehouse to the left (new) warehouse. You are given the two integers <code>n</code> and <code>k</code>, and a 2D integer array <code>time</code> of size <code>k x 4</code> where <code>time[i] = [right<sub>i</sub>, pick<sub>i</sub>, left<sub>i</sub>, put<sub>i</sub>]</code>.</p>
|
|
|
|
<p>The warehouses are separated by a river and connected by a bridge. Initially, all <code>k</code> workers are waiting on the left side of the bridge. To move the boxes, the <code>i<sup>th</sup></code> worker can do the following:</p>
|
|
|
|
<ul>
|
|
<li>Cross the bridge to the right side in <code>right<sub>i</sub></code> minutes.</li>
|
|
<li>Pick a box from the right warehouse in <code>pick<sub>i</sub></code> minutes.</li>
|
|
<li>Cross the bridge to the left side in <code>left<sub>i</sub></code> minutes.</li>
|
|
<li>Put the box into the left warehouse in <code>put<sub>i</sub></code> minutes.</li>
|
|
</ul>
|
|
|
|
<p>The <code>i<sup>th</sup></code> worker is <strong>less efficient</strong> than the j<code><sup>th</sup></code> worker if either condition is met:</p>
|
|
|
|
<ul>
|
|
<li><code>left<sub>i</sub> + right<sub>i</sub> > left<sub>j</sub> + right<sub>j</sub></code></li>
|
|
<li><code>left<sub>i</sub> + right<sub>i</sub> == left<sub>j</sub> + right<sub>j</sub></code> and <code>i > j</code></li>
|
|
</ul>
|
|
|
|
<p>The following rules regulate the movement of the workers through the bridge:</p>
|
|
|
|
<ul>
|
|
<li>Only one worker can use the bridge at a time.</li>
|
|
<li>When the bridge is unused prioritize the <strong>least efficient</strong> worker (who have picked up the box) on the right side to cross. If not, prioritize the <strong>least efficient</strong> worker on the left side to cross.</li>
|
|
<li>If enough workers have already been dispatched from the left side to pick up all the remaining boxes, <strong>no more</strong> workers will be sent from the left side.</li>
|
|
</ul>
|
|
|
|
<p>Return the <strong>elapsed minutes</strong> at which the last box reaches the <strong>left side of the bridge</strong>.</p>
|
|
|
|
<p> </p>
|
|
<p><strong class="example">Example 1:</strong></p>
|
|
|
|
<div class="example-block">
|
|
<p><strong>Input:</strong> <span class="example-io">n = 1, k = 3, time = [[1,1,2,1],[1,1,3,1],[1,1,4,1]]</span></p>
|
|
|
|
<p><strong>Output:</strong> <span class="example-io">6</span></p>
|
|
|
|
<p><strong>Explanation:</strong></p>
|
|
|
|
<pre>
|
|
From 0 to 1 minutes: worker 2 crosses the bridge to the right.
|
|
From 1 to 2 minutes: worker 2 picks up a box from the right warehouse.
|
|
From 2 to 6 minutes: worker 2 crosses the bridge to the left.
|
|
From 6 to 7 minutes: worker 2 puts a box at the left warehouse.
|
|
The whole process ends after 7 minutes. We return 6 because the problem asks for the instance of time at which the last worker reaches the left side of the bridge.
|
|
</pre>
|
|
</div>
|
|
|
|
<p><strong class="example">Example 2:</strong></p>
|
|
|
|
<div class="example-block">
|
|
<p><strong>Input:</strong> <span class="example-io">n = 3, k = 2, time =</span> [[1,5,1,8],[10,10,10,10]]</p>
|
|
|
|
<p><strong>Output:</strong> 37</p>
|
|
|
|
<p><strong>Explanation:</strong></p>
|
|
|
|
<pre>
|
|
<img src="https://assets.leetcode.com/uploads/2024/11/21/378539249-c6ce3c73-40e7-4670-a8b5-7ddb9abede11.png" style="width: 450px; height: 176px;" />
|
|
</pre>
|
|
|
|
<p>The last box reaches the left side at 37 seconds. Notice, how we <strong>do not</strong> put the last boxes down, as that would take more time, and they are already on the left with the workers.</p>
|
|
</div>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>1 <= n, k <= 10<sup>4</sup></code></li>
|
|
<li><code>time.length == k</code></li>
|
|
<li><code>time[i].length == 4</code></li>
|
|
<li><code>1 <= left<sub>i</sub>, pick<sub>i</sub>, right<sub>i</sub>, put<sub>i</sub> <= 1000</code></li>
|
|
</ul>
|