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leetcode-problemset/leetcode-cn/problem (Chinese)/有序数组中差绝对值之和 [sum-of-absolute-differences-in-a-sorted-array].html
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<p>给你一个 <strong>非递减 </strong>有序整数数组 <code>nums</code> 。</p>
<p>请你建立并返回一个整数数组<em> </em><code>result</code>,它跟<em> </em><code>nums</code> 长度相同,且<code>result[i]</code> 等于<em> </em><code>nums[i]</code> 与数组中所有其他元素差的绝对值之和。</p>
<p>换句话说, <code>result[i]</code> 等于 <code>sum(|nums[i]-nums[j]|)</code> ,其中 <code>0 <= j < nums.length</code> 且 <code>j != i</code> (下标从 0 开始)。</p>
<p> </p>
<p><strong>示例 1</strong></p>
<pre>
<b>输入:</b>nums = [2,3,5]
<b>输出:</b>[4,3,5]
<b>解释:</b>假设数组下标从 0 开始,那么
result[0] = |2-2| + |2-3| + |2-5| = 0 + 1 + 3 = 4
result[1] = |3-2| + |3-3| + |3-5| = 1 + 0 + 2 = 3
result[2] = |5-2| + |5-3| + |5-5| = 3 + 2 + 0 = 5。
</pre>
<p><strong>示例 2</strong></p>
<pre>
<b>输入:</b>nums = [1,4,6,8,10]
<b>输出:</b>[24,15,13,15,21]
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>2 <= nums.length <= 10<sup>5</sup></code></li>
<li><code>1 <= nums[i] <= nums[i + 1] <= 10<sup>4</sup></code></li>
</ul>