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33 lines
983 B
HTML
33 lines
983 B
HTML
<p>给定一个字符串 <code>s</code> 和一个整数 <code>k</code>，从字符串开头算起，每计数至 <code>2k</code> 个字符，就反转这 <code>2k</code> 字符中的前 <code>k</code> 个字符。</p>
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<ul>
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<li>如果剩余字符少于 <code>k</code> 个，则将剩余字符全部反转。</li>
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<li>如果剩余字符小于 <code>2k</code> 但大于或等于 <code>k</code> 个，则反转前 <code>k</code> 个字符，其余字符保持原样。</li>
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</ul>
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<p> </p>
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<p><strong>示例 1：</strong></p>
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<pre>
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<strong>输入：</strong>s = "abcdefg", k = 2
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<strong>输出：</strong>"bacdfeg"
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>s = "abcd", k = 2
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<strong>输出：</strong>"bacd"
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>1 <= s.length <= 10<sup>4</sup></code></li>
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<li><code>s</code> 仅由小写英文组成</li>
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<li><code>1 <= k <= 10<sup>4</sup></code></li>
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</ul>
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