mirror of
				https://gitee.com/coder-xiaomo/leetcode-problemset
				synced 2025-11-04 03:33:12 +08:00 
			
		
		
		
	
		
			
				
	
	
		
			31 lines
		
	
	
		
			1.2 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
			
		
		
	
	
			31 lines
		
	
	
		
			1.2 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
<p>Given an <code>m x n</code> binary matrix <code>mat</code>, return <em>the distance of the nearest </em><code>0</code><em> for each cell</em>.</p>
 | 
						|
 | 
						|
<p>The distance between two adjacent cells is <code>1</code>.</p>
 | 
						|
 | 
						|
<p> </p>
 | 
						|
<p><strong>Example 1:</strong></p>
 | 
						|
<img alt="" src="https://assets.leetcode.com/uploads/2021/04/24/01-1-grid.jpg" style="width: 253px; height: 253px;" />
 | 
						|
<pre>
 | 
						|
<strong>Input:</strong> mat = [[0,0,0],[0,1,0],[0,0,0]]
 | 
						|
<strong>Output:</strong> [[0,0,0],[0,1,0],[0,0,0]]
 | 
						|
</pre>
 | 
						|
 | 
						|
<p><strong>Example 2:</strong></p>
 | 
						|
<img alt="" src="https://assets.leetcode.com/uploads/2021/04/24/01-2-grid.jpg" style="width: 253px; height: 253px;" />
 | 
						|
<pre>
 | 
						|
<strong>Input:</strong> mat = [[0,0,0],[0,1,0],[1,1,1]]
 | 
						|
<strong>Output:</strong> [[0,0,0],[0,1,0],[1,2,1]]
 | 
						|
</pre>
 | 
						|
 | 
						|
<p> </p>
 | 
						|
<p><strong>Constraints:</strong></p>
 | 
						|
 | 
						|
<ul>
 | 
						|
	<li><code>m == mat.length</code></li>
 | 
						|
	<li><code>n == mat[i].length</code></li>
 | 
						|
	<li><code>1 <= m, n <= 10<sup>4</sup></code></li>
 | 
						|
	<li><code>1 <= m * n <= 10<sup>4</sup></code></li>
 | 
						|
	<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>
 | 
						|
	<li>There is at least one <code>0</code> in <code>mat</code>.</li>
 | 
						|
</ul>
 |