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leetcode-problemset/leetcode-cn/originData/reconstruct-itinerary.json
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"question": {
"questionId": "332",
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"categoryTitle": "Algorithms",
"boundTopicId": 1873,
"title": "Reconstruct Itinerary",
"titleSlug": "reconstruct-itinerary",
"content": "<p>You are given a list of airline <code>tickets</code> where <code>tickets[i] = [from<sub>i</sub>, to<sub>i</sub>]</code> represent the departure and the arrival airports of one flight. Reconstruct the itinerary in order and return it.</p>\n\n<p>All of the tickets belong to a man who departs from <code>&quot;JFK&quot;</code>, thus, the itinerary must begin with <code>&quot;JFK&quot;</code>. If there are multiple valid itineraries, you should return the itinerary that has the smallest lexical order when read as a single string.</p>\n\n<ul>\n\t<li>For example, the itinerary <code>[&quot;JFK&quot;, &quot;LGA&quot;]</code> has a smaller lexical order than <code>[&quot;JFK&quot;, &quot;LGB&quot;]</code>.</li>\n</ul>\n\n<p>You may assume all tickets form at least one valid itinerary. You must use all the tickets once and only once.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/14/itinerary1-graph.jpg\" style=\"width: 382px; height: 222px;\" />\n<pre>\n<strong>Input:</strong> tickets = [[&quot;MUC&quot;,&quot;LHR&quot;],[&quot;JFK&quot;,&quot;MUC&quot;],[&quot;SFO&quot;,&quot;SJC&quot;],[&quot;LHR&quot;,&quot;SFO&quot;]]\n<strong>Output:</strong> [&quot;JFK&quot;,&quot;MUC&quot;,&quot;LHR&quot;,&quot;SFO&quot;,&quot;SJC&quot;]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/14/itinerary2-graph.jpg\" style=\"width: 222px; height: 230px;\" />\n<pre>\n<strong>Input:</strong> tickets = [[&quot;JFK&quot;,&quot;SFO&quot;],[&quot;JFK&quot;,&quot;ATL&quot;],[&quot;SFO&quot;,&quot;ATL&quot;],[&quot;ATL&quot;,&quot;JFK&quot;],[&quot;ATL&quot;,&quot;SFO&quot;]]\n<strong>Output:</strong> [&quot;JFK&quot;,&quot;ATL&quot;,&quot;JFK&quot;,&quot;SFO&quot;,&quot;ATL&quot;,&quot;SFO&quot;]\n<strong>Explanation:</strong> Another possible reconstruction is [&quot;JFK&quot;,&quot;SFO&quot;,&quot;ATL&quot;,&quot;JFK&quot;,&quot;ATL&quot;,&quot;SFO&quot;] but it is larger in lexical order.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= tickets.length &lt;= 300</code></li>\n\t<li><code>tickets[i].length == 2</code></li>\n\t<li><code>from<sub>i</sub>.length == 3</code></li>\n\t<li><code>to<sub>i</sub>.length == 3</code></li>\n\t<li><code>from<sub>i</sub></code> and <code>to<sub>i</sub></code> consist of uppercase English letters.</li>\n\t<li><code>from<sub>i</sub> != to<sub>i</sub></code></li>\n</ul>\n",
"translatedTitle": "重新安排行程",
"translatedContent": "<p>给你一份航线列表 <code>tickets</code> ,其中 <code>tickets[i] = [from<sub>i</sub>, to<sub>i</sub>]</code> 表示飞机出发和降落的机场地点。请你对该行程进行重新规划排序。</p>\n\n<p>所有这些机票都属于一个从 <code>JFK</code>(肯尼迪国际机场)出发的先生,所以该行程必须从 <code>JFK</code> 开始。如果存在多种有效的行程,请你按字典排序返回最小的行程组合。</p>\n\n<ul>\n\t<li>例如,行程 <code>[\"JFK\", \"LGA\"]</code> 与 <code>[\"JFK\", \"LGB\"]</code> 相比就更小,排序更靠前。</li>\n</ul>\n\n<p>假定所有机票至少存在一种合理的行程。且所有的机票 必须都用一次 且 只能用一次。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/14/itinerary1-graph.jpg\" style=\"width: 382px; height: 222px;\" />\n<pre>\n<strong>输入:</strong>tickets = [[\"MUC\",\"LHR\"],[\"JFK\",\"MUC\"],[\"SFO\",\"SJC\"],[\"LHR\",\"SFO\"]]\n<strong>输出:</strong>[\"JFK\",\"MUC\",\"LHR\",\"SFO\",\"SJC\"]\n</pre>\n\n<p><strong>示例 2</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/14/itinerary2-graph.jpg\" style=\"width: 222px; height: 230px;\" />\n<pre>\n<strong>输入:</strong>tickets = [[\"JFK\",\"SFO\"],[\"JFK\",\"ATL\"],[\"SFO\",\"ATL\"],[\"ATL\",\"JFK\"],[\"ATL\",\"SFO\"]]\n<strong>输出:</strong>[\"JFK\",\"ATL\",\"JFK\",\"SFO\",\"ATL\",\"SFO\"]\n<strong>解释:</strong>另一种有效的行程是 [\"JFK\",\"SFO\",\"ATL\",\"JFK\",\"ATL\",\"SFO\"] ,但是它字典排序更大更靠后。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= tickets.length <= 300</code></li>\n\t<li><code>tickets[i].length == 2</code></li>\n\t<li><code>from<sub>i</sub>.length == 3</code></li>\n\t<li><code>to<sub>i</sub>.length == 3</code></li>\n\t<li><code>from<sub>i</sub></code> 和 <code>to<sub>i</sub></code> 由大写英文字母组成</li>\n\t<li><code>from<sub>i</sub> != to<sub>i</sub></code></li>\n</ul>\n",
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