leetcode-problemset/leetcode-cn/originData/find-and-replace-pattern.json

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            "questionId": "926",
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            "categoryTitle": "Algorithms",
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            "title": "Find and Replace Pattern",
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            "content": "<p>Given a list of strings <code>words</code> and a string <code>pattern</code>, return <em>a list of</em> <code>words[i]</code> <em>that match</em> <code>pattern</code>. You may return the answer in <strong>any order</strong>.</p>\n\n<p>A word matches the pattern if there exists a permutation of letters <code>p</code> so that after replacing every letter <code>x</code> in the pattern with <code>p(x)</code>, we get the desired word.</p>\n\n<p>Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;abc&quot;,&quot;deq&quot;,&quot;mee&quot;,&quot;aqq&quot;,&quot;dkd&quot;,&quot;ccc&quot;], pattern = &quot;abb&quot;\n<strong>Output:</strong> [&quot;mee&quot;,&quot;aqq&quot;]\n<strong>Explanation:</strong> &quot;mee&quot; matches the pattern because there is a permutation {a -&gt; m, b -&gt; e, ...}. \n&quot;ccc&quot; does not match the pattern because {a -&gt; c, b -&gt; c, ...} is not a permutation, since a and b map to the same letter.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;], pattern = &quot;a&quot;\n<strong>Output:</strong> [&quot;a&quot;,&quot;b&quot;,&quot;c&quot;]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= pattern.length &lt;= 20</code></li>\n\t<li><code>1 &lt;= words.length &lt;= 50</code></li>\n\t<li><code>words[i].length == pattern.length</code></li>\n\t<li><code>pattern</code> and <code>words[i]</code> are lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "查找和替换模式",
            "translatedContent": "<p>你有一个单词列表&nbsp;<code>words</code>&nbsp;和一个模式&nbsp;&nbsp;<code>pattern</code>，你想知道 <code>words</code> 中的哪些单词与模式匹配。</p>\n\n<p>如果存在字母的排列 <code>p</code>&nbsp;，使得将模式中的每个字母 <code>x</code> 替换为 <code>p(x)</code> 之后，我们就得到了所需的单词，那么单词与模式是匹配的。</p>\n\n<p><em>（回想一下，字母的排列是从字母到字母的双射：每个字母映射到另一个字母，没有两个字母映射到同一个字母。）</em></p>\n\n<p>返回 <code>words</code> 中与给定模式匹配的单词列表。</p>\n\n<p>你可以按任何顺序返回答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例：</strong></p>\n\n<pre><strong>输入：</strong>words = [&quot;abc&quot;,&quot;deq&quot;,&quot;mee&quot;,&quot;aqq&quot;,&quot;dkd&quot;,&quot;ccc&quot;], pattern = &quot;abb&quot;\n<strong>输出：</strong>[&quot;mee&quot;,&quot;aqq&quot;]\n<strong>解释：\n</strong>&quot;mee&quot; 与模式匹配，因为存在排列 {a -&gt; m, b -&gt; e, ...}。\n&quot;ccc&quot; 与模式不匹配，因为 {a -&gt; c, b -&gt; c, ...} 不是排列。\n因为 a 和 b 映射到同一个字母。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= pattern.length = words[i].length&nbsp;&lt;= 20</code></li>\n</ul>\n",
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