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leetcode-problemset/leetcode-cn/originData/aMhZSa.json
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{
"data": {
"question": {
"questionId": "1000263",
"questionFrontendId": "剑指 Offer II 027",
"categoryTitle": "LCOF2",
"boundTopicId": 910264,
"title": "回文链表",
"titleSlug": "aMhZSa",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "回文链表",
"translatedContent": "<p>给定一个链表的 <strong>头节点&nbsp;</strong><code>head</code><strong>&nbsp;</strong>请判断其是否为回文链表。</p>\n\n<p>如果一个链表是回文,那么链表节点序列从前往后看和从后往前看是相同的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626421737-LjXceN-image.png\" /></strong></p>\n\n<pre>\n<strong>输入:</strong> head = [1,2,3,3,2,1]\n<strong>输出:</strong> true</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626422231-wgvnWh-image.png\" style=\"width: 138px; height: 62px;\" /></strong></p>\n\n<pre>\n<strong>输入:</strong> head = [1,2]\n<strong>输出:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>链表 L 的长度范围为 <code>[1, 10<sup><span style=\"font-size: 9.449999809265137px;\">5</span></sup>]</code></li>\n\t<li><code>0&nbsp;&lt;= node.val &lt;= 9</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶:</strong>能否用&nbsp;O(n) 时间复杂度和 O(1) 空间复杂度解决此题?</p>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 234&nbsp;题相同:<a href=\"https://leetcode-cn.com/problems/palindrome-linked-list/\">https://leetcode-cn.com/problems/palindrome-linked-list/</a></p>\n",
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"difficulty": "Easy",
"likes": 40,
"dislikes": 0,
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * ListNode *next;\n * ListNode() : val(0), next(nullptr) {}\n * ListNode(int x) : val(x), next(nullptr) {}\n * ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n bool isPalindrome(ListNode* head) {\n\n }\n};",
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"langSlug": "java",
"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * int val;\n * ListNode next;\n * ListNode() {}\n * ListNode(int val) { this.val = val; }\n * ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n public boolean isPalindrome(ListNode head) {\n\n }\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def isPalindrome(self, head):\n \"\"\"\n :type head: ListNode\n :rtype: bool\n \"\"\"",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def isPalindrome(self, head: ListNode) -> bool:",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * struct ListNode *next;\n * };\n */\n\n\nbool isPalindrome(struct ListNode* head){\n\n}",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public int val;\n * public ListNode next;\n * public ListNode(int val=0, ListNode next=null) {\n * this.val = val;\n * this.next = next;\n * }\n * }\n */\npublic class Solution {\n public bool IsPalindrome(ListNode head) {\n\n }\n}",
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"lang": "JavaScript",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {boolean}\n */\nvar isPalindrome = function(head) {\n\n};",
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"code": "# Definition for singly-linked list.\n# class ListNode\n# attr_accessor :val, :next\n# def initialize(val = 0, _next = nil)\n# @val = val\n# @next = _next\n# end\n# end\n# @param {ListNode} head\n# @return {Boolean}\ndef is_palindrome(head)\n\nend",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public var val: Int\n * public var next: ListNode?\n * public init() { self.val = 0; self.next = nil; }\n * public init(_ val: Int) { self.val = val; self.next = nil; }\n * public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n func isPalindrome(_ head: ListNode?) -> Bool {\n\n }\n}",
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"lang": "Go",
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"code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n * Val int\n * Next *ListNode\n * }\n */\nfunc isPalindrome(head *ListNode) bool {\n\n}",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n * var next: ListNode = _next\n * var x: Int = _x\n * }\n */\nobject Solution {\n def isPalindrome(head: ListNode): Boolean = {\n\n }\n}",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n * var next: ListNode? = null\n * }\n */\nclass Solution {\n fun isPalindrome(head: ListNode?): Boolean {\n\n }\n}",
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"code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n// pub val: i32,\n// pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n// #[inline]\n// fn new(val: i32) -> Self {\n// ListNode {\n// next: None,\n// val\n// }\n// }\n// }\nimpl Solution {\n pub fn is_palindrome(head: Option<Box<ListNode>>) -> bool {\n\n }\n}",
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"lang": "Racket",
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"code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n (list-node val #f))\n\n|#\n\n(define/contract (is-palindrome head)\n (-> (or/c list-node? #f) boolean?)\n\n )",
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"lang": "Elixir",
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"code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# next: ListNode.t() | nil\n# }\n# defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n @spec is_palindrome(head :: ListNode.t | nil) :: boolean\n def is_palindrome(head) do\n\n end\nend",
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