mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
173 lines
18 KiB
JSON
173 lines
18 KiB
JSON
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"questionId": "749",
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"title": "Shortest Completing Word",
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"titleSlug": "shortest-completing-word",
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"content": "<p>Given a string <code>licensePlate</code> and an array of strings <code>words</code>, find the <strong>shortest completing</strong> word in <code>words</code>.</p>\n\n<p>A <strong>completing</strong> word is a word that <strong>contains all the letters</strong> in <code>licensePlate</code>. <strong>Ignore numbers and spaces</strong> in <code>licensePlate</code>, and treat letters as <strong>case insensitive</strong>. If a letter appears more than once in <code>licensePlate</code>, then it must appear in the word the same number of times or more.</p>\n\n<p>For example, if <code>licensePlate</code><code> = "aBc 12c"</code>, then it contains letters <code>'a'</code>, <code>'b'</code> (ignoring case), and <code>'c'</code> twice. Possible <strong>completing</strong> words are <code>"abccdef"</code>, <code>"caaacab"</code>, and <code>"cbca"</code>.</p>\n\n<p>Return <em>the shortest <strong>completing</strong> word in </em><code>words</code><em>.</em> It is guaranteed an answer exists. If there are multiple shortest <strong>completing</strong> words, return the <strong>first</strong> one that occurs in <code>words</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> licensePlate = "1s3 PSt", words = ["step","steps","stripe","stepple"]\n<strong>Output:</strong> "steps"\n<strong>Explanation:</strong> licensePlate contains letters 's', 'p', 's' (ignoring case), and 't'.\n"step" contains 't' and 'p', but only contains 1 's'.\n"steps" contains 't', 'p', and both 's' characters.\n"stripe" is missing an 's'.\n"stepple" is missing an 's'.\nSince "steps" is the only word containing all the letters, that is the answer.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> licensePlate = "1s3 456", words = ["looks","pest","stew","show"]\n<strong>Output:</strong> "pest"\n<strong>Explanation:</strong> licensePlate only contains the letter 's'. All the words contain 's', but among these "pest", "stew", and "show" are shortest. The answer is "pest" because it is the word that appears earliest of the 3.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= licensePlate.length <= 7</code></li>\n\t<li><code>licensePlate</code> contains digits, letters (uppercase or lowercase), or space <code>' '</code>.</li>\n\t<li><code>1 <= words.length <= 1000</code></li>\n\t<li><code>1 <= words[i].length <= 15</code></li>\n\t<li><code>words[i]</code> consists of lower case English letters.</li>\n</ul>\n",
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"code": "class Solution(object):\n def shortestCompletingWord(self, licensePlate, words):\n \"\"\"\n :type licensePlate: str\n :type words: List[str]\n :rtype: str\n \"\"\"\n ",
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"code": "# @param {String} license_plate\n# @param {String[]} words\n# @return {String}\ndef shortest_completing_word(license_plate, words)\n \nend",
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"code": "class Solution {\n fun shortestCompletingWord(licensePlate: String, words: Array<String>): String {\n \n }\n}",
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"code": "impl Solution {\n pub fn shortest_completing_word(license_plate: String, words: Vec<String>) -> String {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param String $licensePlate\n * @param String[] $words\n * @return String\n */\n function shortestCompletingWord($licensePlate, $words) {\n \n }\n}",
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"code": "(define/contract (shortest-completing-word licensePlate words)\n (-> string? (listof string?) string?)\n\n )",
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"code": "-spec shortest_completing_word(LicensePlate :: unicode:unicode_binary(), Words :: [unicode:unicode_binary()]) -> unicode:unicode_binary().\nshortest_completing_word(LicensePlate, Words) ->\n .",
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"code": "defmodule Solution do\n @spec shortest_completing_word(license_plate :: String.t, words :: [String.t]) :: String.t\n def shortest_completing_word(license_plate, words) do\n\n end\nend",
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"Count only the letters (possibly converted to lowercase) of each word. If a word is shorter and the count of each letter is at least the count of that letter in the licensePlate, it is the best answer we've seen yet."
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],
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"sampleTestCase": "\"1s3 PSt\"\n[\"step\",\"steps\",\"stripe\",\"stepple\"]",
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