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leetcode-problemset/leetcode/originData/defuse-the-bomb.json
2022-05-02 23:44:12 +08:00

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{
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"title": "Defuse the Bomb",
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"content": "<p>You have a bomb to defuse, and your time is running out! Your informer will provide you with a <strong>circular</strong> array <code>code</code>&nbsp;of length of <code>n</code>&nbsp;and a key <code>k</code>.</p>\n\n<p>To decrypt the code, you must replace every number. All the numbers are replaced <strong>simultaneously</strong>.</p>\n\n<ul>\n\t<li>If <code>k &gt; 0</code>, replace the <code>i<sup>th</sup></code> number with the sum of the <strong>next</strong> <code>k</code> numbers.</li>\n\t<li>If <code>k &lt; 0</code>, replace the <code>i<sup>th</sup></code> number with the sum of the <strong>previous</strong> <code>k</code> numbers.</li>\n\t<li>If <code>k == 0</code>, replace the <code>i<sup>th</sup></code> number with <code>0</code>.</li>\n</ul>\n\n<p>As <code>code</code> is circular, the next element of <code>code[n-1]</code> is <code>code[0]</code>, and the previous element of <code>code[0]</code> is <code>code[n-1]</code>.</p>\n\n<p>Given the <strong>circular</strong> array <code>code</code> and an integer key <code>k</code>, return <em>the decrypted code to defuse the bomb</em>!</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> code = [5,7,1,4], k = 3\n<strong>Output:</strong> [12,10,16,13]\n<strong>Explanation:</strong> Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> code = [1,2,3,4], k = 0\n<strong>Output:</strong> [0,0,0,0]\n<strong>Explanation:</strong> When k is zero, the numbers are replaced by 0. \n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> code = [2,4,9,3], k = -2\n<strong>Output:</strong> [12,5,6,13]\n<strong>Explanation:</strong> The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the <strong>previous</strong> numbers.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == code.length</code></li>\n\t<li><code>1 &lt;= n&nbsp;&lt;= 100</code></li>\n\t<li><code>1 &lt;= code[i] &lt;= 100</code></li>\n\t<li><code>-(n - 1) &lt;= k &lt;= n - 1</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def decrypt(self, code, k):\n \"\"\"\n :type code: List[int]\n :type k: int\n :rtype: List[int]\n \"\"\"\n ",
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"hints": [
"As the array is circular, use modulo to find the correct index.",
"The constraints are low enough for a brute-force solution."
],
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Adding an item to a hash.</b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n int id; /* we'll use this field as the key */\\r\\n char name[10];\\r\\n UT_hash_handle hh; /* makes this structure hashable */\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>2. Looking up an item in a hash:</b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>3. 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