leetcode-problemset/leetcode-cn/originData/maximum-distance-in-arrays.json

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            "title": "Maximum Distance in Arrays",
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            "content": "<p>You are given <code>m</code> <code>arrays</code>, where each array is sorted in <strong>ascending order</strong>.</p>\n\n<p>You can pick up two integers from two different arrays (each array picks one) and calculate the distance. We define the distance between two integers <code>a</code> and <code>b</code> to be their absolute difference <code>|a - b|</code>.</p>\n\n<p>Return <em>the maximum distance</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arrays = [[1,2,3],[4,5],[1,2,3]]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> One way to reach the maximum distance 4 is to pick 1 in the first or third array and pick 5 in the second array.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arrays = [[1],[1]]\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == arrays.length</code></li>\n\t<li><code>2 &lt;= m &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= arrays[i].length &lt;= 500</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= arrays[i][j] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>arrays[i]</code> is sorted in <strong>ascending order</strong>.</li>\n\t<li>There will be at most <code>10<sup>5</sup></code> integers in all the arrays.</li>\n</ul>\n",
            "translatedTitle": "数组列表中的最大距离",
            "translatedContent": "<p>给定&nbsp;<code>m</code>&nbsp;个数组，每个数组都已经按照升序排好序了。</p>\n\n<p>现在你需要从两个不同的数组中选择两个整数（每个数组选一个）并且计算它们的距离。两个整数&nbsp;<code>a</code>&nbsp;和&nbsp;<code>b</code>&nbsp;之间的距离定义为它们差的绝对值&nbsp;<code>|a-b|</code>&nbsp;。</p>\n\n<p>返回最大距离。</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>[[1,2,3],[4,5],[1,2,3]]\n<strong>输出：</strong>4\n<strong>解释：</strong>\n一种得到答案 4 的方法是从第一个数组或者第三个数组中选择 1，同时从第二个数组中选择 5 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>arrays = [[1],[1]]\n<b>输出：</b>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == arrays.length</code></li>\n\t<li><code>2 &lt;= m &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= arrays[i].length &lt;= 500</code></li>\n\t<li><code>-10<sup>4</sup> &lt;= arrays[i][j] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>arrays[i]</code>&nbsp;以&nbsp;<strong>升序</strong>&nbsp;排序。</li>\n\t<li>所有数组中最多有&nbsp;<code>10<sup>5</sup></code> 个整数。</li>\n</ul>\n\n<p>&nbsp;</p>\n",
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