mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
16 KiB
JSON
180 lines
16 KiB
JSON
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"questionId": "2532",
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"title": "Remove Letter To Equalize Frequency",
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"content": "<p>You are given a <strong>0-indexed</strong> string <code>word</code>, consisting of lowercase English letters. You need to select <strong>one</strong> index and <strong>remove</strong> the letter at that index from <code>word</code> so that the <strong>frequency</strong> of every letter present in <code>word</code> is equal.</p>\n\n<p>Return<em> </em><code>true</code><em> if it is possible to remove one letter so that the frequency of all letters in </em><code>word</code><em> are equal, and </em><code>false</code><em> otherwise</em>.</p>\n\n<p><strong>Note:</strong></p>\n\n<ul>\n\t<li>The <b>frequency</b> of a letter <code>x</code> is the number of times it occurs in the string.</li>\n\t<li>You <strong>must</strong> remove exactly one letter and cannot choose to do nothing.</li>\n</ul>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> word = "abcc"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Select index 3 and delete it: word becomes "abc" and each character has a frequency of 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> word = "aazz"\n<strong>Output:</strong> false\n<strong>Explanation:</strong> We must delete a character, so either the frequency of "a" is 1 and the frequency of "z" is 2, or vice versa. It is impossible to make all present letters have equal frequency.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= word.length <= 100</code></li>\n\t<li><code>word</code> consists of lowercase English letters only.</li>\n</ul>\n",
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"exampleTestcases": "\"abcc\"\n\"aazz\"",
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"code": "# @param {String} word\n# @return {Boolean}\ndef equal_frequency(word)\n \nend",
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"code": "(define/contract (equal-frequency word)\n (-> string? boolean?)\n )",
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"code": "-spec equal_frequency(Word :: unicode:unicode_binary()) -> boolean().\nequal_frequency(Word) ->\n .",
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"code": "defmodule Solution do\n @spec equal_frequency(word :: String.t) :: boolean\n def equal_frequency(word) do\n \n end\nend",
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"hints": [
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"Brute force all letters that could be removed.",
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"Use a frequency array of size 26."
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],
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"solution": null,
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"status": null,
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"sampleTestCase": "\"abcc\"",
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"metaData": "{\n \"name\": \"equalFrequency\",\n \"params\": [\n {\n \"name\": \"word\",\n \"type\": \"string\"\n }\n ],\n \"return\": {\n \"type\": \"boolean\"\n }\n}",
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