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leetcode-problemset/leetcode/originData/longest-uploaded-prefix.json
2023-12-09 19:57:46 +08:00

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{
"data": {
"question": {
"questionId": "2512",
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"title": "Longest Uploaded Prefix",
"titleSlug": "longest-uploaded-prefix",
"content": "<p>You are given a stream of <code>n</code> videos, each represented by a <strong>distinct</strong> number from <code>1</code> to <code>n</code> that you need to &quot;upload&quot; to a server. You need to implement a data structure that calculates the length of the <strong>longest uploaded prefix</strong> at various points in the upload process.</p>\n\n<p>We consider <code>i</code> to be an uploaded prefix if all videos in the range <code>1</code> to <code>i</code> (<strong>inclusive</strong>) have been uploaded to the server. The longest uploaded prefix is the <strong>maximum </strong>value of <code>i</code> that satisfies this definition.<br />\n<br />\nImplement the <code>LUPrefix </code>class:</p>\n\n<ul>\n\t<li><code>LUPrefix(int n)</code> Initializes the object for a stream of <code>n</code> videos.</li>\n\t<li><code>void upload(int video)</code> Uploads <code>video</code> to the server.</li>\n\t<li><code>int longest()</code> Returns the length of the <strong>longest uploaded prefix</strong> defined above.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input</strong>\n[&quot;LUPrefix&quot;, &quot;upload&quot;, &quot;longest&quot;, &quot;upload&quot;, &quot;longest&quot;, &quot;upload&quot;, &quot;longest&quot;]\n[[4], [3], [], [1], [], [2], []]\n<strong>Output</strong>\n[null, null, 0, null, 1, null, 3]\n\n<strong>Explanation</strong>\nLUPrefix server = new LUPrefix(4); // Initialize a stream of 4 videos.\nserver.upload(3); // Upload video 3.\nserver.longest(); // Since video 1 has not been uploaded yet, there is no prefix.\n // So, we return 0.\nserver.upload(1); // Upload video 1.\nserver.longest(); // The prefix [1] is the longest uploaded prefix, so we return 1.\nserver.upload(2); // Upload video 2.\nserver.longest(); // The prefix [1,2,3] is the longest uploaded prefix, so we return 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= video &lt;= n</code></li>\n\t<li>All values of <code>video</code> are <strong>distinct</strong>.</li>\n\t<li>At most <code>2 * 10<sup>5</sup></code> calls <strong>in total</strong> will be made to <code>upload</code> and <code>longest</code>.</li>\n\t<li>At least one call will be made to <code>longest</code>.</li>\n</ul>\n",
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"lang": "C++",
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"code": "class LUPrefix {\npublic:\n LUPrefix(int n) {\n \n }\n \n void upload(int video) {\n \n }\n \n int longest() {\n \n }\n};\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * LUPrefix* obj = new LUPrefix(n);\n * obj->upload(video);\n * int param_2 = obj->longest();\n */",
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"lang": "Java",
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"code": "class LUPrefix {\n\n public LUPrefix(int n) {\n \n }\n \n public void upload(int video) {\n \n }\n \n public int longest() {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * LUPrefix obj = new LUPrefix(n);\n * obj.upload(video);\n * int param_2 = obj.longest();\n */",
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"lang": "Python",
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"code": "class LUPrefix(object):\n\n def __init__(self, n):\n \"\"\"\n :type n: int\n \"\"\"\n \n\n def upload(self, video):\n \"\"\"\n :type video: int\n :rtype: None\n \"\"\"\n \n\n def longest(self):\n \"\"\"\n :rtype: int\n \"\"\"\n \n\n\n# Your LUPrefix object will be instantiated and called as such:\n# obj = LUPrefix(n)\n# obj.upload(video)\n# param_2 = obj.longest()",
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"lang": "Python3",
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"code": "class LUPrefix:\n\n def __init__(self, n: int):\n \n\n def upload(self, video: int) -> None:\n \n\n def longest(self) -> int:\n \n\n\n# Your LUPrefix object will be instantiated and called as such:\n# obj = LUPrefix(n)\n# obj.upload(video)\n# param_2 = obj.longest()",
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"lang": "C",
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"code": "\n\n\ntypedef struct {\n \n} LUPrefix;\n\n\nLUPrefix* lUPrefixCreate(int n) {\n \n}\n\nvoid lUPrefixUpload(LUPrefix* obj, int video) {\n \n}\n\nint lUPrefixLongest(LUPrefix* obj) {\n \n}\n\nvoid lUPrefixFree(LUPrefix* obj) {\n \n}\n\n/**\n * Your LUPrefix struct will be instantiated and called as such:\n * LUPrefix* obj = lUPrefixCreate(n);\n * lUPrefixUpload(obj, video);\n \n * int param_2 = lUPrefixLongest(obj);\n \n * lUPrefixFree(obj);\n*/",
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"lang": "C#",
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"code": "public class LUPrefix {\n\n public LUPrefix(int n) {\n \n }\n \n public void Upload(int video) {\n \n }\n \n public int Longest() {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * LUPrefix obj = new LUPrefix(n);\n * obj.Upload(video);\n * int param_2 = obj.Longest();\n */",
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"lang": "JavaScript",
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"code": "/**\n * @param {number} n\n */\nvar LUPrefix = function(n) {\n \n};\n\n/** \n * @param {number} video\n * @return {void}\n */\nLUPrefix.prototype.upload = function(video) {\n \n};\n\n/**\n * @return {number}\n */\nLUPrefix.prototype.longest = function() {\n \n};\n\n/** \n * Your LUPrefix object will be instantiated and called as such:\n * var obj = new LUPrefix(n)\n * obj.upload(video)\n * var param_2 = obj.longest()\n */",
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"lang": "TypeScript",
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"code": "class LUPrefix {\n constructor(n: number) {\n \n }\n\n upload(video: number): void {\n \n }\n\n longest(): number {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * var obj = new LUPrefix(n)\n * obj.upload(video)\n * var param_2 = obj.longest()\n */",
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"lang": "PHP",
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"code": "class LUPrefix {\n /**\n * @param Integer $n\n */\n function __construct($n) {\n \n }\n \n /**\n * @param Integer $video\n * @return NULL\n */\n function upload($video) {\n \n }\n \n /**\n * @return Integer\n */\n function longest() {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * $obj = LUPrefix($n);\n * $obj->upload($video);\n * $ret_2 = $obj->longest();\n */",
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"lang": "Swift",
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"code": "\nclass LUPrefix {\n\n init(_ n: Int) {\n \n }\n \n func upload(_ video: Int) {\n \n }\n \n func longest() -> Int {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * let obj = LUPrefix(n)\n * obj.upload(video)\n * let ret_2: Int = obj.longest()\n */",
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"lang": "Kotlin",
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"code": "class LUPrefix(n: Int) {\n\n fun upload(video: Int) {\n \n }\n\n fun longest(): Int {\n \n }\n\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * var obj = LUPrefix(n)\n * obj.upload(video)\n * var param_2 = obj.longest()\n */",
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"lang": "Dart",
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"code": "class LUPrefix {\n\n LUPrefix(int n) {\n \n }\n \n void upload(int video) {\n \n }\n \n int longest() {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * LUPrefix obj = LUPrefix(n);\n * obj.upload(video);\n * int param2 = obj.longest();\n */",
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"lang": "Go",
"langSlug": "golang",
"code": "type LUPrefix struct {\n \n}\n\n\nfunc Constructor(n int) LUPrefix {\n \n}\n\n\nfunc (this *LUPrefix) Upload(video int) {\n \n}\n\n\nfunc (this *LUPrefix) Longest() int {\n \n}\n\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * obj := Constructor(n);\n * obj.Upload(video);\n * param_2 := obj.Longest();\n */",
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"lang": "Ruby",
"langSlug": "ruby",
"code": "class LUPrefix\n\n=begin\n :type n: Integer\n=end\n def initialize(n)\n \n end\n\n\n=begin\n :type video: Integer\n :rtype: Void\n=end\n def upload(video)\n \n end\n\n\n=begin\n :rtype: Integer\n=end\n def longest()\n \n end\n\n\nend\n\n# Your LUPrefix object will be instantiated and called as such:\n# obj = LUPrefix.new(n)\n# obj.upload(video)\n# param_2 = obj.longest()",
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"lang": "Scala",
"langSlug": "scala",
"code": "class LUPrefix(_n: Int) {\n\n def upload(video: Int) {\n \n }\n\n def longest(): Int = {\n \n }\n\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * var obj = new LUPrefix(n)\n * obj.upload(video)\n * var param_2 = obj.longest()\n */",
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"lang": "Rust",
"langSlug": "rust",
"code": "struct LUPrefix {\n\n}\n\n\n/** \n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl LUPrefix {\n\n fn new(n: i32) -> Self {\n \n }\n \n fn upload(&self, video: i32) {\n \n }\n \n fn longest(&self) -> i32 {\n \n }\n}\n\n/**\n * Your LUPrefix object will be instantiated and called as such:\n * let obj = LUPrefix::new(n);\n * obj.upload(video);\n * let ret_2: i32 = obj.longest();\n */",
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"lang": "Racket",
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"code": "(define lu-prefix%\n (class object%\n (super-new)\n \n ; n : exact-integer?\n (init-field\n n)\n \n ; upload : exact-integer? -> void?\n (define/public (upload video)\n )\n ; longest : -> exact-integer?\n (define/public (longest)\n )))\n\n;; Your lu-prefix% object will be instantiated and called as such:\n;; (define obj (new lu-prefix% [n n]))\n;; (send obj upload video)\n;; (define param_2 (send obj longest))",
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"lang": "Erlang",
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"code": "-spec lu_prefix_init_(N :: integer()) -> any().\nlu_prefix_init_(N) ->\n .\n\n-spec lu_prefix_upload(Video :: integer()) -> any().\nlu_prefix_upload(Video) ->\n .\n\n-spec lu_prefix_longest() -> integer().\nlu_prefix_longest() ->\n .\n\n\n%% Your functions will be called as such:\n%% lu_prefix_init_(N),\n%% lu_prefix_upload(Video),\n%% Param_2 = lu_prefix_longest(),\n\n%% lu_prefix_init_ will be called before every test case, in which you can do some necessary initializations.",
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"lang": "Elixir",
"langSlug": "elixir",
"code": "defmodule LUPrefix do\n @spec init_(n :: integer) :: any\n def init_(n) do\n \n end\n\n @spec upload(video :: integer) :: any\n def upload(video) do\n \n end\n\n @spec longest() :: integer\n def longest() do\n \n end\nend\n\n# Your functions will be called as such:\n# LUPrefix.init_(n)\n# LUPrefix.upload(video)\n# param_2 = LUPrefix.longest()\n\n# LUPrefix.init_ will be called before every test case, in which you can do some necessary initializations.",
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"Maintain an array keeping track of whether video “i” has been uploaded yet."
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