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leetcode-problemset/leetcode-cn/problem (English)/上级经理已离职的公司员工(English) [employees-whose-manager-left-the-company].html
2023-12-09 18:53:53 +08:00

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<p>Table: <code>Employees</code></p>
<pre>
+-------------+----------+
| Column Name | Type |
+-------------+----------+
| employee_id | int |
| name | varchar |
| manager_id | int |
| salary | int |
+-------------+----------+
In SQL, employee_id is the primary key for this table.
This table contains information about the employees, their salary, and the ID of their manager. Some employees do not have a manager (manager_id is null).
</pre>
<p>&nbsp;</p>
<p>Find the IDs of the employees whose salary is strictly less than <code>$30000</code> and whose manager left the company. When a manager leaves the company, their information is deleted from the <code>Employees</code> table, but the reports still have their <code>manager_id</code> set to the manager that left.</p>
<p>Return the result table ordered by <code>employee_id</code>.</p>
<p>The result format is in the following example.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input: </strong>
Employees table:
+-------------+-----------+------------+--------+
| employee_id | name | manager_id | salary |
+-------------+-----------+------------+--------+
| 3 | Mila | 9 | 60301 |
| 12 | Antonella | null | 31000 |
| 13 | Emery | null | 67084 |
| 1 | Kalel | 11 | 21241 |
| 9 | Mikaela | null | 50937 |
| 11 | Joziah | 6 | 28485 |
+-------------+-----------+------------+--------+
<strong>Output:</strong>
+-------------+
| employee_id |
+-------------+
| 11 |
+-------------+
<strong>Explanation:</strong>
The employees with a salary less than $30000 are 1 (Kalel) and 11 (Joziah).
Kalel&#39;s manager is employee 11, who is still in the company (Joziah).
Joziah&#39;s manager is employee 6, who left the company because there is no row for employee 6 as it was deleted.
</pre>