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leetcode-problemset/leetcode-cn/originData/tvdfij.json
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{
"data": {
"question": {
"questionId": "1000248",
"questionFrontendId": "LCR 012",
"categoryTitle": "Algorithms",
"boundTopicId": 910251,
"title": "寻找数组的中心下标",
"titleSlug": "tvdfij",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "寻找数组的中心下标",
"translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code> ,请计算数组的 <strong>中心下标 </strong>。</p>\n\n<p>数组<strong> 中心下标</strong><strong> </strong>是数组的一个下标,其左侧所有元素相加的和等于右侧所有元素相加的和。</p>\n\n<p>如果中心下标位于数组最左端,那么左侧数之和视为 <code>0</code> ,因为在下标的左侧不存在元素。这一点对于中心下标位于数组最右端同样适用。</p>\n\n<p>如果数组有多个中心下标,应该返回 <strong>最靠近左边</strong> 的那一个。如果数组不存在中心下标,返回 <code>-1</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,7,3,6,5,6]\n<strong>输出:</strong>3\n<strong>解释:</strong>\n中心下标是 3 。\n左侧数之和 sum = nums[0] + nums[1] + nums[2] = 1 + 7 + 3 = 11 \n右侧数之和 sum = nums[4] + nums[5] = 5 + 6 = 11 ,二者相等。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1, 2, 3]\n<strong>输出:</strong>-1\n<strong>解释:</strong>\n数组中不存在满足此条件的中心下标。</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [2, 1, -1]\n<strong>输出:</strong>0\n<strong>解释:</strong>\n中心下标是 0 。\n左侧数之和 sum = 0 ,(下标 0 左侧不存在元素),\n右侧数之和 sum = nums[1] + nums[2] = 1 + -1 = 0 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-1000 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 724&nbsp;题相同:&nbsp;<a href=\"https://leetcode-cn.com/problems/find-pivot-index/\">https://leetcode-cn.com/problems/find-pivot-index/</a></p>\n",
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"translatedName": "数组",
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"name": "Prefix Sum",
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"code": "class Solution {\npublic:\n int pivotIndex(vector<int>& nums) {\n\n }\n};",
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