mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
22 KiB
JSON
180 lines
22 KiB
JSON
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"questionId": "130",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1889,
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"title": "Surrounded Regions",
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"titleSlug": "surrounded-regions",
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"content": "<p>Given an <code>m x n</code> matrix <code>board</code> containing <code>'X'</code> and <code>'O'</code>, <em>capture all regions that are 4-directionally surrounded by</em> <code>'X'</code>.</p>\n\n<p>A region is <strong>captured</strong> by flipping all <code>'O'</code>s into <code>'X'</code>s in that surrounded region.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/xogrid.jpg\" style=\"width: 550px; height: 237px;\" />\n<pre>\n<strong>Input:</strong> board = [["X","X","X","X"],["X","O","O","X"],["X","X","O","X"],["X","O","X","X"]]\n<strong>Output:</strong> [["X","X","X","X"],["X","X","X","X"],["X","X","X","X"],["X","O","X","X"]]\n<strong>Explanation:</strong> Notice that an 'O' should not be flipped if:\n- It is on the border, or\n- It is adjacent to an 'O' that should not be flipped.\nThe bottom 'O' is on the border, so it is not flipped.\nThe other three 'O' form a surrounded region, so they are flipped.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> board = [["X"]]\n<strong>Output:</strong> [["X"]]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 <= m, n <= 200</code></li>\n\t<li><code>board[i][j]</code> is <code>'X'</code> or <code>'O'</code>.</li>\n</ul>\n",
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"translatedTitle": "被围绕的区域",
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"translatedContent": "给你一个 <code>m x n</code> 的矩阵 <code>board</code> ，由若干字符 <code>'X'</code> 和 <code>'O'</code> ，找到所有被 <code>'X'</code> 围绕的区域，并将这些区域里所有的 <code>'O'</code> 用 <code>'X'</code> 填充。\n<div class=\"original__bRMd\">\n<div>\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/xogrid.jpg\" style=\"width: 550px; height: 237px;\" />\n<pre>\n<strong>输入：</strong>board = [[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"O\",\"O\",\"X\"],[\"X\",\"X\",\"O\",\"X\"],[\"X\",\"O\",\"X\",\"X\"]]\n<strong>输出：</strong>[[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"O\",\"X\",\"X\"]]\n<strong>解释：</strong>被围绕的区间不会存在于边界上，换句话说，任何边界上的 <code>'O'</code> 都不会被填充为 <code>'X'</code>。 任何不在边界上，或不与边界上的 <code>'O'</code> 相连的 <code>'O'</code> 最终都会被填充为 <code>'X'</code>。如果两个元素在水平或垂直方向相邻，则称它们是“相连”的。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>board = [[\"X\"]]\n<strong>输出：</strong>[[\"X\"]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 <= m, n <= 200</code></li>\n\t<li><code>board[i][j]</code> 为 <code>'X'</code> 或 <code>'O'</code></li>\n</ul>\n</div>\n</div>\n",
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