mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
182 lines
26 KiB
JSON
182 lines
26 KiB
JSON
{
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"questionId": "1079",
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"questionFrontendId": "1022",
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"categoryTitle": "Algorithms",
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"boundTopicId": 3365,
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"title": "Sum of Root To Leaf Binary Numbers",
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"titleSlug": "sum-of-root-to-leaf-binary-numbers",
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"content": "<p>You are given the <code>root</code> of a binary tree where each node has a value <code>0</code> or <code>1</code>. Each root-to-leaf path represents a binary number starting with the most significant bit.</p>\n\n<ul>\n\t<li>For example, if the path is <code>0 -> 1 -> 1 -> 0 -> 1</code>, then this could represent <code>01101</code> in binary, which is <code>13</code>.</li>\n</ul>\n\n<p>For all leaves in the tree, consider the numbers represented by the path from the root to that leaf. Return <em>the sum of these numbers</em>.</p>\n\n<p>The test cases are generated so that the answer fits in a <strong>32-bits</strong> integer.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/04/04/sum-of-root-to-leaf-binary-numbers.png\" style=\"width: 400px; height: 263px;\" />\n<pre>\n<strong>Input:</strong> root = [1,0,1,0,1,0,1]\n<strong>Output:</strong> 22\n<strong>Explanation: </strong>(100) + (101) + (110) + (111) = 4 + 5 + 6 + 7 = 22\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [0]\n<strong>Output:</strong> 0\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 1000]</code>.</li>\n\t<li><code>Node.val</code> is <code>0</code> or <code>1</code>.</li>\n</ul>\n",
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"translatedTitle": "从根到叶的二进制数之和",
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"translatedContent": "<p>给出一棵二叉树，其上每个结点的值都是 <code>0</code> 或 <code>1</code> 。每一条从根到叶的路径都代表一个从最高有效位开始的二进制数。</p>\n\n<ul>\n\t<li>例如，如果路径为 <code>0 -> 1 -> 1 -> 0 -> 1</code>，那么它表示二进制数 <code>01101</code>，也就是 <code>13</code> 。</li>\n</ul>\n\n<p>对树上的每一片叶子，我们都要找出从根到该叶子的路径所表示的数字。</p>\n\n<p>返回这些数字之和。题目数据保证答案是一个 <strong>32 位 </strong>整数。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2019/04/04/sum-of-root-to-leaf-binary-numbers.png\" />\n<pre>\n<strong>输入：</strong>root = [1,0,1,0,1,0,1]\n<strong>输出：</strong>22\n<strong>解释：</strong>(100) + (101) + (110) + (111) = 4 + 5 + 6 + 7 = 22\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [0]\n<strong>输出：</strong>0\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的节点数在 <code>[1, 1000]</code> 范围内</li>\n\t<li><code>Node.val</code> 仅为 <code>0</code> 或 <code>1</code> </li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer\n */\n function sumRootToLeaf($root) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer}\ndef sum_root_to_leaf(root)\n\nend",
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